1.1.2 Basic Principles and Techniques (Expressions of Reagent Concentration) Flashcards
Molarity is moles per Kg solvent
Molality is moles per L of solution
T or F
F
Molarity = Moles/L
Molality = Moles/Kg
What is the formula for Molarity?
M = (g/L) / MW
MW = Molecular weight
IF g/dL is given, what is the formula?
M = ((g/dL) / MW) x 10
OR
M = ((g/dL) x 10)) / MW
Equivalent weights per L of Solutions
a. Normality
b. Nomality
c. Nomarity
a
Formula for Equivalent weights?
EW = MW / Valence
What is valence?
a. Number of Hydrogen
b. Number of hydroxyl (OH)
c. Number of electrons gain or loss (Charge)
d. Both a and c
f. All of the above
f
What is the formula for Normality?
N or Eq/L
=
(g/L) / EW
EW = Equivalent weight
Amount of solute per 100 total units of solution
a. Dilution
b. % v/w
c. % w/v
d. Normality
c
If g/100mL = g/dL
IF Molarity is given
g/dL = (M x MW)/10
IF Normality is given
g/dL = (N x EW)/10
T or F
T
Expression of relative concentration
a. Dilution
b. Ratio
a
Amount of something relative to another
a. Dilution
b. Ratio
b
What is the formula for Dilution?
D = SV / TV
OR
D = SV / (SV + DV)
SV = Solute volume
DV = Diluent volume
TV = Total Volume
What is the Molarity of a 1L solution containing 72g of H2O
(H=1, O=16)
4
Solution:
Add the Molar mass:
H = 1 x 2 = 2
O = 16 x 1 = 16
16 + 2 = 18
MW = 18
(72g/L) / 18
= 4
What is the Molarity of 0.234 mol of CoCl2 in 0.527 L of solution
0.444
Solution:
The Moles is already given just divide it by the solution
REMEMBER: M = Moles/L of solution
What is the molarity of 20.54 g of Al(NO3)3 in 1575 mL of solution/
Al = 26.982
N = 14.007
O = 16.000
0.0612 / 6.1 x 10^-2
Solution:
Add the molar mass:
Al: 26.982 x 1 = 26.982
N: 14.007 x 3 = 42.021
O: 16.000 x 9 = 144
MW = 213.003
CONVERT mL to L
1575 -> 1.575
20.54/213.003 = 0.0964
0.0964/1.575
= 0.0612