Ch 9 Section 2 Flashcards

1
Q

the balanced chemical equation is the key step in all stoichiometric calculations because the mole ratio is

A

obtained directly from it

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2
Q

solving any reaction stoichiometry problem must begin with a

A

balanced equation

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3
Q

chemical equations help us plan the amounts of reactants to use in a chemical reaction without having to

A

run the reactions in the laboratory

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4
Q

theoretical stoichiometry calculations tell us the amounts of reactants and products for a given chemical reaction under

A

ideal conditions, in which reactants are completely converted into products

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5
Q

many reactions do not proceed such that all reactants are completely converted into

A

products

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6
Q

theoretical stoichiometric calculations allow us to determine the maximum amount of product that could be obtained in a reaction when the reactants are not

A

pure or byproducts are formed in addition to the expected products

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7
Q

the plan for a simple mole conversion problem requires one conversion factor– the stoichiometric mole ratio of the unknown substance to the

A

given substance from the balanced equation

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8
Q

to solve this type of problem (mole to mole) simply multiply the

A

known quantity by the appropriate conversion factor

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9
Q

given quantity x conversion factor =

A

unknown quantity

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10
Q

amount of given substance (mol) x mol unknown/ mol given →

A

amount of unknown substance (mol)

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11
Q

the plan for mole-to-gram conversions requires two conversion factors– the mole ratio for the unknown substance to the given substance and the molar mass of the

A

unknown substance for the mass conversion.

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12
Q

amount of given mol unknown/ Mmof unknown g/
substance x mol given x 1 mol unknown
=

A

mass of unknown substance

g

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13
Q

the plan to calculate the amount in moles from a given mass of another substance requires two additional pieces of data:

A

molar mass of the given substance and the mole ratio

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14
Q

because the known quantity is a mass, the conversion factor will need to be 1 mol divided by

A

molar mass

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15
Q

mass of given substance (g) x 1 mol given/ Mm of given (g) x mol unknown/ mol given -

A

amount of unknown substance (mol)

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16
Q

mass of given substance (g) x 1 mol given/ Mm of given (g) x mol unknown/ mol given x Mm of unknown (g)/ 1 mol unknown =

A

mass of unknown substance (g)

17
Q

mass-mass calculations are more practical than other

A

mole calculations

18
Q

you can never measure moles

A

directly

19
Q

you are generally required to calculate the amount in moles of a substance from its

A

mass, which you can measure in the lab

20
Q

3 additional pieces of data are needed to solve mass-mass problems:

A

molar mass of the given substance, the mole ratio, and the molar mass of the unknown substance