Ch 9 Section 2 Flashcards
the balanced chemical equation is the key step in all stoichiometric calculations because the mole ratio is
obtained directly from it
solving any reaction stoichiometry problem must begin with a
balanced equation
chemical equations help us plan the amounts of reactants to use in a chemical reaction without having to
run the reactions in the laboratory
theoretical stoichiometry calculations tell us the amounts of reactants and products for a given chemical reaction under
ideal conditions, in which reactants are completely converted into products
many reactions do not proceed such that all reactants are completely converted into
products
theoretical stoichiometric calculations allow us to determine the maximum amount of product that could be obtained in a reaction when the reactants are not
pure or byproducts are formed in addition to the expected products
the plan for a simple mole conversion problem requires one conversion factor– the stoichiometric mole ratio of the unknown substance to the
given substance from the balanced equation
to solve this type of problem (mole to mole) simply multiply the
known quantity by the appropriate conversion factor
given quantity x conversion factor =
unknown quantity
amount of given substance (mol) x mol unknown/ mol given →
amount of unknown substance (mol)
the plan for mole-to-gram conversions requires two conversion factors– the mole ratio for the unknown substance to the given substance and the molar mass of the
unknown substance for the mass conversion.
amount of given mol unknown/ Mmof unknown g/
substance x mol given x 1 mol unknown
=
mass of unknown substance
g
the plan to calculate the amount in moles from a given mass of another substance requires two additional pieces of data:
molar mass of the given substance and the mole ratio
because the known quantity is a mass, the conversion factor will need to be 1 mol divided by
molar mass
mass of given substance (g) x 1 mol given/ Mm of given (g) x mol unknown/ mol given -
amount of unknown substance (mol)