Kaplan General Chemistry: Chapter 12 Electrochemistry Flashcards

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1
Q

galvanic cells utilize ___ reaction

A

spontaneous

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2
Q

electrolytic cells utilize ___ reactions

A

nonspontaneous

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3
Q

concentration cells utilize ___ reactions

A

spontaneous

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4
Q

oxidation occurs at the ___

reduction occurs at the ____

A

oxidation, anode

reduction, cathode

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5
Q

if EMF is +, the G is:

if EMF is -, then G is:

A

EmF is the voltage/ electrical potential difference of the cell.
if EMF is +, the G is: SPONTANEOUS
if EMF is -, then G is: NONSPONTANEOUS

Recall: G=-nFE

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6
Q

movement of electrons is ALWAYS ___ to ___

A

anode to cathode

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7
Q

in galvanic cells, the chemical that wants to be reduced (+E) is at the ____

A

cathode. it IS being reduced. results in a >0 cell potential.

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8
Q

why do electrolytic cells need an input of energy?

A

becaues they house nonspontaneous reactions. This oxidation-reduction reaction is driving by an ecternal voltage souce. The amount of chemical change induced in an electrolytic cell is directly proportional to the number of moles of electrons that are exchanged during the oxidation reduction reaction.

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9
Q

How can voltage be calculated using the Nersnt Equation?

A
Ecell = E"cell - (RT/nF)(lnQ)
Ecell= E''cell - (0.0592/n)logQ
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10
Q

in a galvanic cell, the anode = ____ and the cathode ___

A

in galvanic: anode = negative, cathode = positive.

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11
Q

in an electrolytic cell, the node = ____ and the cathode = _____

A

anode = positive elctrode because it is attached to the POSITIVE pole of the external voltage source, and attracts ANIONs

cathode = negative electrode because it is attached to the negative pole of the external voltage source and attracts CATIONS from the solution.

although there is a charge difference, oxidation still takes place at the anode and reduction still takes place at the cathode in BOTH types of cells. regardless of charge designation, the cathode ALWAYS attracts cations and the anode ALWAYS attracts anions.

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12
Q

Unit of Newtons

A

J/m = Kgm/s^2

Recall: Work = Fd therefore F=W/d units: J/m

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13
Q

unit breakdown of a Joule

A

J = Nm = Kgm^2/s^2

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14
Q

How to calculate EMF od cell

A

E’cell = E’reduced,cathode - E’redanode

or Ecell = E’reducedcathode + E’oxidizedanode

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15
Q

how to measure the work done by an electrochemical apparatus

A

W=qV

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16
Q

useful G equations

A

deltaG’= -RTlnKeq
deltaG’= -nFE’cell = -RTlnK
deltaG=G’ + RTlnQ

Ecell = E’cell - (RT/nF)lnQ