normal lung alveolar gas exchange Flashcards
1
Q
partial pressure of gas in ambient air
A
- Pgas= Fgas x Patm
- Pgas = partial pressure of a gas
- Fgas = concentration of a gas (.21)
- Patm = atmospheric pressure (760mm Hg)
2
Q
partial pressure of H2O vapor conducting zone (PH2O)
A
- 47 mm Hg
3
Q
partial pressure of of gas in inspired air
A
- PIgas = Fgas (Patm - PH2O)
4
Q
partial pressure of O2 in alveolus (PAO2)
A
- 100 mm Hg
- gas equation (Patm - 47)fO2- PCO2/R
(760-47).21-40/.8
5
Q
partial pressure of CO2 in alveolus (PACO2)
A
- 40 mm Hg
- inverse to alveolar ventilation
- hyper and hypoventilation
6
Q
partial pressure of O2 in arterial (PaO2)
A
- 100 mm Hg
7
Q
partial pressure of CO in arterial (PaCO2)
A
- 40 mm Hg
8
Q
partial pressure of O2 in alveolus (PAO2)
partial pressure of O2 in arterial (PaO2)
A
= equals to 100 mm Hg diffusion will take place
is at equilibrium
- SAME CONCEPT IN CO2 = 40 mm Hg
9
Q
diffuse first out of the capillary O2 or CO2
A
- CO2 due to its high solubility even thou it has a smaller pressure gradient
- CO > CO2 > O2 pressure is constant and equal for all
10
Q
PAO2 is proportional to Patm, fO2 and PaO2
A
- Patm
- fO2
11
Q
respiratory zone
A
- alveoli are found
- PAO2 = (Patm - 47)fO2- PCO2/R
- IN THE ALVEOLUS
12
Q
conducting zone
A
- PiO2 = (Patm - 47)fO2
13
Q
diffusion capacity of the lung
A
- PERFUSION- LIMITED
- DIFFUSION- LIMITED
14
Q
PERFUSION-LIMITED
A
- substance EQUILIBRATES between the capillary and interstitium
15
Q
DIFFUSION-LIMITED
A
- substance DOES NOT equilibrate between capillary and interstitium
