Calculations I & II Flashcards

conversions

1
Q

fl oz to mL

A

1 fl oz = 29.57 mL

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2
Q

oz to g

A

1 oz = 28.4 g

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3
Q

grains to g

A

1 gr = 64.8 g

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4
Q

left ear abbreviation

A

AS

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5
Q

right ear abbreviation

A

AD

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6
Q

both ears abbreviation

A

AU

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7
Q

left eye abbreviation

A

OS

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8
Q

right eye abbreviation

A

OD

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9
Q

both eyes abbreviation

A

OU

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10
Q

steroid equivalents

A

prednisone 5mg
prednisolone 5mg
methylprednisolone 4mg
triamcinolone 4mg
dexamethasone 0.75mg
betamethasone 0.5mg
hydrocortisone 20mg
cortisone 25mg

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11
Q

how to calculate ratio strength from a concentration such as 5mg/mL

A

convert to % strength (w/w, w/v, v/v) then convert to ratio strength represented as 1/X (1:X) which has NO UNITS

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12
Q

does ratio strength have units

A

no

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13
Q

how to convert 0.00022% to ppm

A

set up proportion
0.00022g = x
100mL 1,000,000
x = # ppm

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14
Q

specific gravity
use
equation
SG >1 =
SG <1 =

A

SG helps convert between volume and weight of the same substance

SG = g/mL
SG >1 = heavier than water
SG <1 = lighter than water

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15
Q

what equation is used for dilution of a substance

A

C1Q1 = C2Q2
* need same units on each side

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16
Q

In alligation, what % is in the top left, bottom left, and middle

A

top left = higher %
bottom left = lower %
middle = desired %

17
Q

In an osmolarity question, how does the equation change if they are asking for mOsm/L vs milliosmoles

A

for mOsm/L the numerator must be normalized to 1L
ex) have 10g in 200mL = x / 1000mL where x is now the g/L in the numerator
mOsm/L = g in 1 L x # particles x 1000
MW

if asking for mOsm –> can leave as original grams

mOsm = g actual x # particles x 1000
MW

18
Q

How do you determine the # particles for the osmolarity equation
mOsm/L = g in 1 L x # particles x 1000
MW

A

particles = number of dissociated components if dissolved in water
dextrose, mannitol = 1 (non-ionic, do not dissolve)
KCl, NaCl, NaC2H3O2, MgSO4 = 2 particles each
CaCL2 = 3 particles

19
Q

You can _____ mOm/L (osmolarty) of multiple substances together to get the osmolarity of the solution

A. divide
B. subtract
C. add
D. multiply

A

C. add

20
Q

For isotonicity, how do you determine the isotonicity factor (i)?

A

Depends on the number of dissociated ions. Add 0.8 to i each time you increase the # dissoc ions by 1

dissoc ions i value
1 1
2 1.8
3 2.6
4 3.4
5 4.2

21
Q

What substances are isotonic?

A

bodily fluids, eye drops, nasal solutions, TPN

22
Q

What does isotonic mean

A

osmotic pressure = that of NaCl 0.9% which is 300 mOsm/kg

23
Q

Define SCE (“E”)

A

sodium chloride equivalents
Helps determine the relationship between the amount of drug that produces a specific osmolarity and the amount of NaCl that produces the same osmolarity

24
Q

Equation to determine the SCE (“E”) of a drug

A

SCE aka E = 58.5 x (i)
MW x 1.8

25
Q

How to solve a SCE isotonicity question

A
  1. calculate E with equation
  2. g drug x E = g NaCl it will represent
  3. use the concentration of NaCl 0.9% to determine how much “total” NaCl is needed for isotonicity
  4. subtract. 3-2 = amount of additional NaCl needed to create isotonicity
26
Q

mEq
equation

A

mEq = mg x valence
MW

valence = # of negatively charged ions

27
Q

i value vs # particles vs valence

A

i is the isotonicity factor determined by the number of dissociated ions
#particles is the # particles that are dissociated
valence = # negatively charged ions once dissociated