16A.1 Flashcards
oxidation is
loss of electrons
reduction is
gain of electrons
when an element is oxidized its oxidation number
increases
when an element is reduced its oxidation number
decreases
standard electrode potential is also
redox potentail
standard electrode potential is also
redox potential
what happens to metals when they are placed in water
they have a very small tendency for them to lose electrons and from a solution of positive ions
how is this (M^n+(aq) + ne^-1 eq M(s)) eq formed
when a metal is put in water it loses electrons and forms a positive ion solution, so within a short time, there will be a build-up of electrons on the surface of the metal, due to the electrostatic attraction between the electrons on the surface of the metal and the positive ions formed, some of the positive ions will regain their electrons and become part of the metal surface, eventually a dynamic equilibrium will form
the eq formed between the positive metal ion and its electrons in water is given by
M^n+(aq) + ne^-1 eq M(s)
the more reactive the metal in a half-cell is
the eq will lie further to the left, which means more significant tendencies to release electrons so greater negative charge on the metal and more positive ions in the solution
what is the absolute potential difference
the potential difference between the electrons on the surface of the metal and the solution of positive ions of that metal
what is the rs between absolute potential difference and reactivity of the metals
as the metal becomes more reactive the V increases
why can’t we measure the absolute potential difference directly
we can connect the metal electrode to one terminal (of the circuit), but the other terminal would have to be connected to the solution which isn’t possible. and we can’t connect the terminal to other metal dipped into the water because then that would create its own potential difference.
how can we measure absolute potential difference of a half cell
create a refence potential electrode (standard hydrogen electrode) then measure the potential difference between the reference electrode and the metal electrode
what is the reference electrode of choice
standard hydrogen electrode
how does the standard hydrogen electrode work
hydrogen gas at pressure of 100KPa (1 bar) being bubbled over a piece of platinum foil covered with porous platinum, dipped into a solution of acid (H2SO4) with [H^+] at 1 mol dm^-3, at temp of 298K
why do we cover platinum with porous platinum
it has a large surface area and allows the Eq between hydrogen ions in the solution and the hydrogen gas to be established quickly
what is the standard hydrogen electrode half cell (its half equation)
page 161
Importance of using student conditions
the position of Eq changes by altering the conditions so fair comparisons we need standard conditions
what are standard conditions
- 100KPa (1 bar), 298K, concentration in solution of 1 mol dm^-3
what is a half cell
it is one half that makes the electrochemical cell, and two half cells complete one cell