13A.4 Flashcards

1
Q

the only factor that can change Kc is

A

temperature

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2
Q

what happens when there is a change in concentration of one of the components in an equilibrium mixture

A

there will be an immediate change in the reaction quotient, meaning that the Qc does not equal the Kc so the eq composition changes until they equal each other

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3
Q

what is the reaction quotient

A

the measure of the relative amount of products and reactants present in a reaction at any given time

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4
Q

what is the expression of Qc

A

page 67 (not there are not at Eq)

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5
Q

what happens when we increases the concentration of one of the reactants, and how does the equilibrium return after its been altered

A

the value of Qc would decreases and it wont equal Kc, for the eq to be re-established the magnitude of the denominator in the Qc expression(the reactants) has to decreases, because of the a subsequent event will cause the numerator for the expression of Qc (products) to increase in value. the two values will keep adjusting unit Qc=Kc again and the equilibrium will be re-established, the net result of all of this will cause the eq to shift to the right

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6
Q

why can we equate n1/V1 = n2/V2 when we add more moles to same equation

A

because if the pressure is constant and the gas acts like a ideal gas we can say the number of moles is proportional to the volume of the gas

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7
Q

when Qc > Kc what must happen to the eq

A

shift to the left the denominator must increase

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7
Q

when Qc > Kc what must happen to the eq

A

shift to the left the denominator must increase

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8
Q

when Qc < Kc what must happen to the Eq

A

shift to the right the denominator must decrease

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9
Q

what are the two reasons why qualitive predictions wont work for adding mole to gases

A
  1. the increase of the number of moles to the reactant should shift the eq to the right
  2. increase in volume should increase to the left
    so we don’t know which way it truly goes
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10
Q

how can you calculate where the equilibrium would shift

A

page 68

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11
Q

the change in pressure, at a constant temp, on an eq system containing only gases hove no effect on either

A

Kc or Kp

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12
Q

if the partial pressure of one gas changes the overall effect on Kp

A

can be predicted using the same method in in page 68

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13
Q

what is the relationship between partial pressure of gases and the total pressure in a gaseous system

A

if the total pressure in a gaseous system increases or decreases the partial pressure of all the gases would also increase or decrease

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14
Q

how do you calculate the shift of the eq when the total pressure of a gaseous system is changed

A

page 69

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15
Q

why doesn’t the catalyst have any effect on the eq constant

A

because a catalyst both increases the rate of the forward and backward reaction, it makes it possible for the eq to be established faster, but it wont increase the effect of the reactant or the products

16
Q

why cant we find the influence of a catalyst on Kc

A

because the Kc expression only factors the components in the stoichiometric equation which the catalyst doesn’t appear in