Vanders Renal Questions and Key Comments Flashcards
Ch 1 Key Concept. In addition to excreting waste, the kidneys perform many necessary functions in partnership with other body organ systems.
Ch 1 Key Concept. The kidneys regulate the excretion of many substances at a rate that balances their input, thereby maintaining appropriate body content of those substances.
Ch 1 Key Concept. A major function of the kidneys is to regulate the volume and osmolality of extracellular fluid volume.
Ch 1 Key Concept. The kidneys are composed mainly of tubules and closely associated blood vessels.
Ch 1 Key Concept. Each functional renal unit is composed of a filtering component (glomerulus) and a transporting tubular component (the nephron and collecting duct).
Ch 1 Key Concept. The tubules are made up of multiple segments with distinct functions.
Ch 1 Key Concept. Basic renal mechanisms consist of filtering a large volume, reabsorbing most of it, and adding substances by secretion, and, in some cases, synthesis.
1-1 Renal corpuscles are located
a. along the cortico-medullary border.
b. throughout the cortex.
c. throughout the cortex and outer medulla.
d. throughout the whole kidney.
1�1. (b) Renal corpuscles are distributed throughout the cortex, which
includes the region just above the cortico-medullary border
(i.e., the juxtamedullary region). None are in the medulla.
1-2 Relative to the number of glomeruli, how many loops of Henle,
and how many collecting ducts are there?
a. Same number of loops of Henle; same number of collecting
ducts.
b. Fewer loops of Henle; fewer collecting ducts.
c. Same number of loops of Henle; fewer collecting ducts.
d. Same number of loops of Henle; more collecting ducts.
1�2. (c) Each glomerulus is associated with a nephron, which includes a
loop of Henle. Each collecting duct is formed from the
coalescence of several nephrons.
1-3 It is possible for the body to be in balance for a substance when
a. the amount of the substance in the body is constant.
b. the amount of the substance in the body is higher than normal.
c. the input of the substance into the body is higher than normal.
d. in all of these situations.
1�3. (d) Balance implies that input equals output, which can occur at
normal or abnormal levels of amounts in the body, or normal or
abnormal input, so long as the inputs are matched by equal
outputs.
1-4 The macula densa is a group of cells located in the wall of
a. Bowman�s capsule.
b. the afferent arteriole.
c. the end of the thick ascending limb.
d. the descending thin limb.
1�4. (c) The macula densa cells are located in the tubule where it passes
between the afferent and efferent arterioles. This location is at
the end of the thick ascending limb of the loop of Henle just
before it becomes the distal tubule.
1-5 The volume of fluid entering the tubules by glomerular filtration
in one day is typically
a. about three times the renal volume.
b. about the same as the volume filtered by all the capillaries in
the rest of the body.
c. about equal to the circulating plasma volume.
d. more than the total volume of water in the body.
1�5. (d) A healthy young 70-kg person contains about 42 L of water
(~60% of body weight), and filters up to 180 L of plasma each
day.
1-6 In the context of the kidney, secretion of a substance implies that
a. it is transported from tubular cells into the tubular lumen.
b. it is filtered into Bowman�s capsule.
c. it is present in the final urine that is excreted.
1�6. (a) Secretion implies transport from tubular cell to the lumen. Most
often the substance entered the cell from the blood, but it could
also be synthesized and then transported.
Ch 1 Key Note. We use the term �reabsorption� to describe the movement of filtered substances
back into the blood because they are re-entering the blood. �Absorption� describes
the original entrance of consumed substances from the GI tract into the blood.
Ch 2 Key Concept. The kidneys have a very large blood flow relative to their mass that is regulated for functional reasons rather than
metabolic demand
Ch 2 Key Concept. Glomerular capillary pressure is determined by the
relative resistances of afferent arterioles, which precede
the glomerulus, and efferent arterioles, which follow it.
Ch 2 Key Concept. Glomerular filtration proceeds through a three-layered
barrier that restricts filtration of large macromolecules
such as albumin.
Ch 2 Key Concept. Negative surface charge on the filtration barrier restricts
filtration of negatively charged solutes more than positively
charged solutes.
Ch 2 Key Concept. The glomerular filtration rate (GFR) is determined by the
permeability of the filtration barrier and net filtration
pressure (NFP).
Ch 2 Key Concept. Net filtration pressure (NFP) varies mainly with
hydrostatic and oncotic pressures in the glomerular
capillaries.
Ch 2 Key Concept. Control of the resistances of the afferent and efferent
arterioles permits independent control of glomerular
filtration rate and renal blood flow.
Ch 2 Key Concept. Autoregulation of vascular resistances keeps GFR within
limits in the face of large variations in arterial pressure.
2-1. Blood enters the renal medulla immediately after passing through
which vessels?
a. Arcuate arteries
b. Peritubular capillaries
c. Afferent arterioles
d. Efferent arterioles
2�1. (d) Most efferent arterioles feed peritubular capillaries, but those
associated with juxtamedullary glomeruli feed vascular bundles
that descend into the medulla.
2-2. Which cell type is the main determinant of the filterability of
plasma solutes?
a. Mesangial cell.
b. Podocyte.
c. Endothelial cell.
d. Vascular smooth muscle.
2�2. (d) While various factors affect how much plasma is filtered, the
glycocalyx, basement membrane, and particularly the slit
diaphragms bridging the foot processes of podocytes, all of
which are extracellular, are the key determinants of what is
filtered.
2-3. Which one of the following is NOT subject to physiological
control on a moment-to-moment basis?
a. Hydrostatic pressure in glomerular capillaries.
b. Selectivity of the filtration barrier.
c. Filtration coefficient.
d. Resistance of efferent arterioles.
2�3. (a) Rapid control is exerted over the contractile properties of
vascular smooth muscle that in turn affects hydrostatic pressure
in glomerular capillaries.
2-4. A substance is freely filtered and has a certain concentration in
peripheral plasma. You would expect the substance to have
virtually the same concentration in
a. the glomerular filtrate.
b. the afferent arteriole.
c. the efferent arteriole.
d. all of these places.
2�4. (d) Other than larger molecules that are only partially or slightly
filtered, the plasma concentrations of a small freely filtered
substance are not altered by filtration because water and the
substance in question are filtered in the same proportions.
2-5. In the face of a 20% decrease in arterial pressure, GFR decreases
by only 2%. What could account for this finding?
a. The resistances of the afferent and efferent arterioles both
decrease equally.
b. Glomerular mesangial cells contract.
c. Efferent arteriolar resistance increases.
d. Afferent arteriolar resistance increases.
2�5. (c) The lowering of pressure upstream from the glomerulus is offset
by contraction of the efferent arteriole, an action that by itself
raises glomerular capillary pressure. The net effect leaves
glomerular capillary pressure almost unchanged.
2-6. The hydrostatic pressure within the glomerular capillaries
a. is much higher than in most peripheral capillaries.
b. is about the same as in the peritubular capillaries.
c. decreases markedly along the length of the capillaries.
d. is generally lower than the oncotic pressure in the glomerular
capillaries.
2�6. (a) Glomerular capillary pressure starts at about 60 mm Hg and
falls very little along the length of the capillaries. This value is
far higher than in most peripheral capillaries.
Ch 3 Key Concept. Clearance expresses the rate at which a substance is
removed from the plasma and excreted in the urine (renal
clearance), or removed by all mechanisms combined
(metabolic clearance rate), and is always quantified in
units of volume per time.
Ch 3 Key Concept. Renal clearance of any substance is calculated by a
clearance formula relating urine flow to urine and plasma
concentrations.
Ch 3 Key Concept. Inulin clearance is the best measure GFR because inulin is
freely filtered and neither secreted nor reabsorbed.
Ch 3 Key Concept. Para-aminohippurate clearance can be used as an
estimate of renal blood flow.
Ch 3 Key Concept. Creatinine clearance is used as practical measure of GFR.
Ch 3 Key Concept. Plasma creatinine concentration and/or cystatin C is used
clinically as an indicator of the GFR.
Ch 3 Key Concept. Renal scintigraphy assesses the function of each kidney
separately.
3-1. We can calculate the renal clearance of any substance if we know
which pair of values?
a. Urine flow rate and urine concentration
b. Plasma concentration and urine concentration
c. GFR and urinary excretion rate
d. Plasma concentration and urinary excretion rate
3�1. (d) The excretion rate of a substance divided by its plasma
concentration yields the clearance.
3-2. A drug X has a short plasma half-life and must be administered
frequently to maintain therapeutic levels. The urinary
concentration of X is much higher than the plasma concentration.
A substantial amount of X also appears in the feces. What can we
say about the renal clearance of X compared with the metabolic
clearance rate of X?
a. The metabolic clearance rate is higher than the renal
clearance.
b. The renal clearance is higher than the metabolic clearance
rate.
c. The two clearances are the same.
d. There is insufficient information to answer the question.
3�2. (a) The metabolic clearance rate represents the sum of all clearance
routes. Since there are two major routes of clearance (kidneys
and feces) the metabolic clearance must be higher than either
one alone. The fact that the drug has a higher urinary
concentration than plasma concentration mainly reflects the
reabsorption of water.
3-3. Inulin clearance is measured twice; the first time at a low inulin
infusion rate, and the second time at a higher infusion rate that
results in a higher plasma inulin concentration during the test.
Assuming the kidneys behave the same in both cases, which
measurement will yield a higher inulin clearance?
a. The first
b. The second
c. Both measurements are the same.
d. There is insufficient information to answer the question.
3�3. (c) In the second test both the plasma concentration and filtered
load (and hence rate of excretion) are increased, yielding
offsetting effects on the calculation.
Which of the following indicates correct relative renal
clearances?
a. Sodium clearance is greater than urea clearance.
b. PAH clearance is greater than inulin clearance. c. Urea clearance is greater than PAH clearance.
d. Creatinine clearance is greater than PAH clearance.
3�4. (b) Normally the relative clearance rates are: PAH > creatinine ?
inulin > urea > sodium.
3-5. An acute poisoning episode destroys 80% of a patient�s nephrons.
If the plasma urea concentration prior to the episode was 5
mmol/L, and assuming dietary protein remains the same, what is
the expected value of plasma urea now?
a. 4 mmol/L
b. 6.25 mmol/L
c. 25 mmol/L
d. Continuously rising
3�5. (d) Anything that increases the removal of a substance from the
blood, whether by increased filtration, increased metabolism, or
less reabsorption, increases clearance.
Ch 4 Key Concept. Flux from lumen to interstitium can be transcellular, using
separate transport steps in the apical and basolateral
membranes, or paracellular, around the cells through tight
junctions.
Ch 4 Key Concept. The kidneys move solutes across membranes by multiple transport mechanisms, including channels, uniporters,
multiporters, and primary active transporters.
Ch 4 Key Concept. The kidneys regulate excretion by regulating channels and
transporters in epithelial cell membranes.
Ch 4 Key Concept. Water crosses epithelial barriers by movement down
osmotic gradients (from regions of lower to higher
osmolality).
Ch 4 Key Concept. Volume reabsorption is a multistep process involving
transport across epithelial membranes from lumen to
interstitium, and bulk flow from interstitium to peritubular
capillaries driven by Starling forces.
Ch 4 Key Concept. The reabsorption of water concentrates all remaining
tubular solutes, increasing the driving force for their
passive reabsorption by diffusion.
Ch 4 Key Concept. All reabsorptive processes have a limit on how fast they
can occur, either because the substance leaks back into the
lumen (gradient-limited systems) or because the
transporters saturate (Tm systems).
4-1. A healthy patient has a normal plasma osmolality (close to 300
100 mOsm/kg). If 100 mmol of solutes are reabsorbed iso-osmotically
from the proximal tubule, approximately how much water is
reabsorbed with the solute?
a. 100 mL
b. 300 mL
c. 333 mL
d. 1000 mL
4�1. (c) 100 mmol is the amount of solute in one-third of a kilogram of
filtrate (333 mL), so this much water accompanies the
reabsorbed solute.