Test 2: Wk6: 1 Renal transport mechanisms and clearance - Mangiarua Flashcards

1
Q

3 basic renal processes

A

1 glomerular filtration
2 tubular secretion
3 tubular reabsorbtion

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2
Q

Glomerular filtration

A

bulk-flow of essentially protein-free plasma from the

glomerular capillaries into Bowman’s capsule.

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3
Q

Glomerular filtration is what type of transport

A

passive; no active

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4
Q

Tubular secretion

A

transfer of materials from the peritubular-capillary plasma to the
tubular lumen

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5
Q

Tubular secretion transport

A

Both active and passive transport

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6
Q

Tubular secretion selectivity

A

high

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7
Q

tubular secretion occurs where

A

throughout the length of the nephron

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8
Q

Tubular reabsorption

A

transfer of materials from the lumen of the tubule to the

peritubular-capillary plasma.

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9
Q

Tubular reabsorption selectivity

A

high

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10
Q

Tubular reabsorption transport

A

Both active and passive transport

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11
Q

tubular reabsorption occurs where

A

throughout the length of the nephron

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12
Q

— charged macromolecules are
restricted far more than —molecules, while — charged molecules
are restricted less.

A

negative, neutral, positive

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13
Q

As molecular weight (and therefore size) —, filterability —, so
that proteins with a molecular weight above — d are hardly filtered at all.

A

increase, declines, 70,000

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14
Q

best index of kidney function

A

GFR

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15
Q

GFR 60-89

A

mild kidney dz

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16
Q

GFR 30-59

A

Moderate chronic renal insufficiency

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17
Q

GFR 15-29

A

Severe chronic renal insufficiency

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18
Q

GFR <15

A

End Stage Renal Failure

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19
Q

Renal Clearance

A

volume of plasma from which all of a substance has been removed and excreted into urine per unit time

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20
Q

What is used for Measurement of GFR

A

inulin

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21
Q

— is freely filtered at the glomerulus and not reabsorbed or secreted into tubule

A

inulin

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22
Q

GFR =

A

urine flow x inulin conc. urine / inulin conc. plasma

GFR = V x Uin / Pin

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23
Q

In order to determine the rate at which plasma is filtered into Bowman’s space, a chemical which meets the following criteria is used (6)

A

1) Not bound to plasma proteins.
2) Not electrically charged.
3) Freely filtered.
4) Not lost by reabsorption from tubular fluid to peritubular fluid.
5) Not gained by secretion from peritubular fluid into tubular fluid.
6) All that is filtered is excreted.

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24
Q

Clearance of Inulin

A

GFR = Uin x V / Pin = Cin

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25
Inulin clearance refers to the
Inulin clearance refers to the milliliters of plasma from which all inulin has been removed by the kidney each minute
26
Inulin clearance is independent of
plasma inulin conc. and urine flow
27
Creatinine
endogenous substance that estimates GFR
28
Clearance of Creatinine
GFR = Ccr = Ucr x V / Pcr
29
Creatinine --- GFR
slightly overestimates
30
--- concentration is used to follow pts over long period of chronic renal dz
Creatinine
31
Renal Clearance Ca =
Ca = Va x V / Pa
32
Ca > Cin
cleared by filtration and secretion
33
Cb < Cin
some of b is reabsorbed
34
Diffusion:
* requires an electrochemical gradient, | * “downhill” transport
35
Facilitated diffusion:
requires an electrochemical gradient + carriers; exhibits specificity, saturability, and competition, • “downhill” transport.
36
Primary active transport
requires carriers; exhibits specificity, saturability, and competition, • “uphill” transport. Requires energy; splitting of ATP.
37
Secondary active transport
• requires carriers; exhibits specificity, saturability, and competition, • one substance “downhill” transport, the other “uphill” transport, • cotransport (or symport), • countertransport (or antiport).
38
diffusion between cells
paracellular
39
“across” the cell
transcellular
40
--- used for measurement of effective renal plasma flow
PAH
41
PAH is filtered ---
at glomerulus
42
PAH undergoes no significant
tubular reabsorbtion
43
--- can be used to estimate RPF (Renal Plasma Flow)
Clearance of PAH
44
PAH is a foreign compound so it needs to be
infused
45
ERPF
Effective Renal Plasma Flow
46
ERPF =
ERPF = CPAH = V x UPAH / PPAH
47
the effective renal plasma flow Underestimates true RPF by ---%
10%
48
The actual renal plasma flow can be obtained by dividing the --- by ---
ERPF by excretion ratio of PAH
49
equation for calculation RPF
E = A - V / A A conc. in renal arterial plasma V conc. in renal venous plasma
50
Urate filterability
free
51
more than 90% if filtered urate is reabsorbed where
early in prox tubule
52
urate secretion
active tubular secretion in late prox tubule
53
urate is --- regulated
homeostatically
54
urate undergoes both --- and ---
active reabsorption and active secretion
55
K filterability
free
56
67% of K reabsorbed in
prox tubule
57
20% of K is reabsorbed in
TAL of LOH
58
--- is reabsorbed or secreted in the late nephron depending on diet
K
59
K is --- regulated
homeostatically
60
Reabsorption rate =
Filtered load – Excretion rate
61
Secretion rate =
Excretion rate – Filtered load
62
Filtered load =
GFR x [plasma]
63
Excretion rate =
V x [urine]