OAR Limits Flashcards

1
Q

What are the main sources of data for OAR limits?

A

QUANTEC, Emami et al, Data from clinical trails

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2
Q

What data is given by Emami regarding OARs?

A

TD50/5 (dose that gives 50%NTCP in 5 years), TD5/5, volume dependences.

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3
Q

What is the advantage of using the recent 2013 Emami data over the original 1991 data?

A

The new data is more precise than the original; the endpoints are better specified.

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4
Q

What does QUANTEC stand for?

A

Quantitative Analysis of Normal Tissue Effects in the Clinic

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5
Q

What is the source of QUANTEC?

A

Int. J. Radiation Oncology Biol. Phys., Vol. 76, No. 3, Supplement

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6
Q

Name 4 of the organ specific QUANTEC papers.

A
Brain
Optic Chiasm
Brain stem
Spinal cord
Ear
Parotid
Larynx/Pharynx
Lung
Heart
Esophagus
Liver
Stomach/small bowel
Kidney
Bladder
Rectum
Penile Bulb
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7
Q

What is the main outcome from the QUANTEC papers?

A

Toxicity scoring

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8
Q

What is the general principle of how single numbers are obtained from complicated data to get a toxicity outcome?

A

3D dose distribution > discard anatomical, physiological and spatial data > compute NTCP (or extract single point//global data)

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9
Q

What data is required to convert published dose limits into local dose limits?

A

Total dose to OAR
Number of fractions OAR dose is given in
Effective volume of OAR that receives that dose
The α/β ratio used in the analysis in the specific paper/information source being used for your calculation

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10
Q

What is the alpha/beta ratio for a tumour?

A

10

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11
Q

What is the alpha/beta ratio for an OAR?

A

3

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12
Q

If using the data in a given paper, what α/β ratio should be used when calculating the BED for your clinical situation when comparing with that paper?

A

The same as the paper.

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13
Q

What is the equation to calculate EQD2?

A

D * [ 1 + d / (α/β) ] / [ 1 + 2 / (α/β) ]
Simplified:
D * [ (α/β) + d ] / [ (α/β) + 2 ]

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14
Q

What is the equation for EQDX(α/β)?

A

D * [ 1 + d / (α/β) ] / [ 1 + X / (α/β) ]

where X is equivalent dose in X Gy per fraction

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15
Q

What is the special case for EQDX(α/β)?

A

EQD0: sub in 0 to get EQDx = BED

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