Math Unit 2 Test Flashcards

1
Q

The graph of a quadratic is called a…

A

PARABOLA

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2
Q

The ? of a parabola is the point on the graph with the greatest y-coordinate if the graph opens down or the least y-coordinate if the graph opens up

A

VERTEX

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3
Q

When the quadratic relation is used to model a situation, the y-coordinate of the vertex corresponds to an ? (Maximum/Minimum) value.

A

OPTIMAL

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4
Q

Depending on the ? of the parabola, you will either have a ? or ? value of the equation

A

DIRECTION OF OPENING
MAXIMUM or MINIMUM

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5
Q

The ? value is always the y-value of the Vertex

A

MAXIMUM/MINIMUM

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6
Q

standard form + characteristics

A

y = a^2 + bx + c
- c is the y-intercept
- ‘a’ is positive it OPENS UP
- ‘a’ is negative it OPENS DOWN

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7
Q

vertex form + characteristics

A

y = a(x-h)^2 + k
- (h,K) is the VERTEX
- ‘a’ is positive it OPENS UP
- ‘a’ is negative it OPENS DOWN

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8
Q

factored form + characteristics

A

y = a(x-r)(x-s)
- ‘r’ and ‘s’ are the x-intercepts
- ‘a’ is positive it OPENS UP
- ‘a’ is negative it OPENS DOWN

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9
Q

Maximum if ‘a’ is …

A

NEGATIVE

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10
Q

Minimum if ‘a’ is …

A

POSITIVE

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11
Q

Maximum/Minimum Value is …

A

‘k’

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12
Q

Equation of Axis of Symmetry…

A

x = h

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13
Q

Steps to Completing the Square:

A
  1. Put brackets on the first 2 terms
  2. Factor out the value in front of x2
  3. Take ½ of the value in front of x and Square it
  4. Add AND Subtract that value into the bracket
  5. Remove the Subtracted value from the bracket, (multiply by ‘a’ when removing)
  6. Factor the trinomial bracket (it’s ALWAYS a Perfect Square Trinomial)
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14
Q

Revenue =

A

Cost x Number Sold

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15
Q

Area =

A

L X W

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16
Q

Steps for Real Life Applications of Quadratic Functions

A
  1. Create a let statement
  2. Ensure that there’s only one variable
  3. Sub that equation in
  4. Foil until you have a Quadratic Function
  5. Complete the square
  6. `Max/Min is K, X will be the ticket price or width
17
Q

Solving a Quadratic Equations means to

A

find the unknown variable.

18
Q

Steps to Solving Quadratic Equations by Factoring and Quadratic Formula

A
  1. Place all numbers and variables on one side of the equation = 0
  2. Strategies for solving Quadratic Equations
    - Factoring
    - Quadratic Formula
19
Q

Quadratic Formula

A

x = -b +/- √ b^2 - 4ac / 2a

20
Q

Vertex form - (h,k)

A

y = a(x-h)^2 + k

21
Q

Factored form - x-intercepts r & s

A

y = a (x-r)(x-s)

22
Q

My steps to Finding the Quadratic Equations

A
  1. Examine the question -
    a. if you’re given a vertex (h,K) and a point (x,y) solve using vertex form
    b. If you’re given the x-intercepts (r and s) and a point (x,y) solve using factored form
  2. Sub everything else in
  3. Solve for a
  4. Rearrange the Equation
23
Q

Nature of Roots =

A

How many Points of Intersection (x-intercepts) does the Quadratic Equation have?

24
Q

Discriminant =

A

b^2 - 4ac

25
Q

When b^2 - 4ac > 0

A

2 x-intercepts

26
Q

When b^2 - 4ac = 0

A

1 x-intercept

27
Q

When b^2 - 4ac < 0

A

0 x-intercepts

28
Q

Steps for The Discriminant and the Nature of Roots

A
  1. Use the discriminant and plug in the numbers
  2. If asked for k do the same then solve for K
29
Q

Steps for Applications of Quadratic Equations

A
  1. Write let statement for what you are trying to find
  2. Create a (Quadratic) Equation
  3. Solve for the unknown variable using:
    a) Factoring
    b) Quadratic Equation
30
Q

A linear function and a quadratic function can intersect at a ? of ? points

A

MAXIMUM
2

31
Q

Steps for Intersection of Linear and Quadratic Functions:

A
  1. Rewrite the LINEAR equation in the form of y=mx+b
  2. Substitute the LINEAR equations into the QUADRATIC equation (for the y variable)
  3. Solve for the unknown variable (Factoring or Quadratic formula)
  4. Substitute the found variable into either original equation (the Linear is usually a nice option) to find the other variable
  5. State the Point(s) of Intersection