Acids and Bases - pOH and OH- Calculations

Question 1

pOH and OH- Relationships

Answer 1

• expresses OH- concentration as the negative logarithm of the OH- concentration in moles per liter
• pOH = -log[OH-]
• [OH-] = 10^-pOH

Question 2

what is the pOH of a 4.8*10^-3 M OH- solution?

Answer 2

• pOH = -loh[OH-]
• pOH = -log[4.8*10^-3]
• pOH = 2.32

Question 3

what is the [OH-] if hte pOH is 11.34?

Answer 3

• [OH-] = 10^-pOH
• [OH-] = 10^-11.34
• [OH-] = 4.6*10^-12 M OH-