Acids and Bases - pH and pOH Strong Acids and Bases

Question 1

pH and pOH Relationships

Answer 1

• pH = -log[H+]

- pOH = -log[OH-]

Question 2

molarity of strong acids

Answer 2

• molarity is equal to [H+] for monoprotic acids, 0.10M HCl -> 0.10M H+ + 0.10M Cl-
• sulfuric acid is only strong diprotic acid, 0.10M H2SO4 -> 2(0.10M) H+ + 0.10M SO4^2-

Question 3

molarity is equal to [OH-] for monobasic bases

• 0.023M naOH -> 0.023M Na+ + 0.023M OH-
• formula unit for dibasic bases:
  0. 023M Ca(OH)2 -> 0.023M Ca^2+ + 2(0.023M) OH-

Answer 3

• pOH = -log[OH-]
• -log [0.023M]
• pOH = 1.64
• pH = 14 - 1.64 = 12.36
• • -log[2(0.23M)] (Ca(OH)2
• • pOH = 1.34
• • pH = 12.66