11/29/22 - Electrons and Periodic Trends Flashcards
Does similar electron configuration confer similar chemical behavior?
Yes
What are inner electrons?
Those in the noble gas core plus any additional complete d-sublevels
What are outer electrons?
Those in the highest occupied energy level (all electrons at the highest n value)
Which electrons are valence electrons?
In main-group elements, they are the outer electrons
In transition elements, they are the outer electrons plus the highest d-sublevel electrons
Which electrons participate in forming bonds?
Valence
The electron configuration for F is
[He]2s^2 2p^5
How many inner electrons are there?
2 from the He
The electron configuration for F is
[He]2s^2 2p^5
How many outer electrons are there?
7 because the highest energy level is n = 2, which has 7 electrons
The electron configuration for F is
[He]2s^2 2p^5
How many valence electrons are there?
- F is a main-group element, so the outer electrons are the valence electrons
The electron configuration for Cr is
[Ar]4s^1 3d^5
How many inner electrons are there? (Ar is Z = 18)
18 from Ar
The electron configuration for Cr is
[Ar]4s^1 3d^5
How many outer electrons are there?
- The highest energy level is n=4, which has 1 electron.
The electron configuration for Cr is
[Ar]4s^1 3d^5
How many valence electrons are there?
- Cr is a transition element, so its 1 outer electron and 5 3d electrons are valence
The electron configuration for Br is
[Ar]4s^2 3d^10 4p^5
How many inner electrons are there? (Ar is Z = 18)
28, there are 18 from Ar and 10 from the complete 3d sublevel
The electron configuration for Br is
[Ar]4s^2 3d^10 4p^5
How many outer electrons are there?
- There are 7 electrons in the n=4 energy level
The electron configuration for Br is
[Ar]4s^2 3d^10 4p^5
How many valence electrons are there?
- As a main group element, the valence electrons of Br are the outer electrons
Why is the electron configuration of copper
[Ar]4s^1 3d^10 instead of 4s^2 3d^9?
Because half-filled and fully filled sublevels are more stable.
Likewise Cr is [Ar]4s^1 3d^5