AAMC FL3 CPF Flashcards

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1
Q

aufbau principle of electron configuration

A

electrons fill low energy orbitals (closer to the nucleus) before they fill higher energy ones.

in low to high energy:
1s > 2s 2p > 3s 3p > 4s > 3d > 4p …

draw out aufbau (1) until perfect
- up to n = 8

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2
Q

s block / d block / p block orbital filling

d block ions

A

s block: 4s orbital filling
d block: 3d
p block: 4p

** in d block ions (transition elements), the 4s orbital behaves as the outermost, highest energy orbital

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3
Q

how many electrons in each orbital s/p/d/f

A

s = 1 orbital = 2 electrons max

p = 3 orbitals = 6 max

d = 5 = 10 max

f = 7 = 14 max

total max # of electrons: 32 (fourth level)

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4
Q
electron configuration of
[Ar]
Sc
Ti
V
Cr
Mn
Fe
Co
Ni
Cu
Zn

aka your d block transition metals

A

the energy of the 3d orbitals becomes slightly less than that of the 4s

[Ar] is used to represent 1s2 2s2 2p6 3s2 3p6

Sc	[Ar] 3d1 4s2
Ti	[Ar] 3d2 4s2
V	[Ar] 3d3 4s2
Cr	[Ar] 3d5 4s1
Mn	[Ar] 3d5 4s2
Fe	[Ar] 3d6 4s2
Co	[Ar] 3d7 4s2
Ni	[Ar] 3d8 4s2
Cu	[Ar] 3d10 4s1
Zn	[Ar] 3d10 4s2
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5
Q

electronic configuration of
neutral iron and iron (III)

what ions are lost first during ionization

A

Fe: 1s2 2s2 2p6 3s2 3p6 3d6 4s2

Fe3+: 1s2 2s2 2p6 3s2 3p6 3d5

4s electrons are lost first during ionization, thus the 4s orbital must have a higher energy than the 3d orbitals.

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6
Q

quantum numbers

A

n = principal quantum number = refers to size of orbital and energy level

l = azimuthal quantum number = number of subshells; describes shape of orbital

ml = magnetic quantum number = orbital sub-type; range of -s to +s

ms = spin quantum number = can only be -0.5 or +0.5; have to add up to 0 when paired

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7
Q

what do differing amounts of an isomeric product indicate

A

For a thermodynamic mixture of isomeric products, the relative mole ratio of products is directly related to the relative stability of these products.

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8
Q

calculate capacitance in terms of charge and velocity

calculate energy stored in a capacitor

A

C = Q / V
= charge over voltage
[C] = farad, F = C / V

E = mc^2
E = 0.5CV^2
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9
Q

how do you determine the relative stability of isomers

A

the relative thermodynamic stability of isomers can be determined based on the amount of heat produced when the compounds are combusted; less heat, greater stability.

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10
Q

energy in terms of wavelengths and frequencies

A

Relevant equation: E = hf

Wavelength and energy have inverse relationships; frequency and energy have direct relationships.

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11
Q

what is needed to reliably obtain Vo versus substrate concentration data to calculate KM and Vmax using Michaelis−Menten enzyme kinetics

A

Initial velocity is measured under steady state conditions.

Solution pH remains constant at all substrate concentrations.

The concentration of enzyme is lower than that of substrate.

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12
Q

what compound can coordinate calcium ions

A

coordinate = interact w

only a lewis base can coordinate Ca2+

lewis base: any atom that can donate a lone pair of electrons

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13
Q

porphyrin

A

eg. heme

The basic unit of a porphyrin is the pyrrole ring, a five-sided heterocycle containing one nitrogen atom.

be able to draw (1)

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14
Q

equilibrium constant for DNA unfolding

also, delta Go for it

A

Keq = [unfolded]/[native] as the unfolded DNA is considered to be a product.

Thus, ΔG′° = −RTlnKeq = −RTln([unfolded]/[native]).

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15
Q

continuity equation

+ its relationship to blood flow

A

density1 * A1 * v1 = density2 * A2 * v2

thus, if u is the speed of flow in the capillary bed, then A × v = n × a × u

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16
Q

when light passes thru one medium to another, what happens

A

speed and wavelength changes but frequency doesn’t

thus, according to v = wavelength * frequency, speed and wavelength have a direct relationship

light will also bend / refract

17
Q

example of trigonal bipyramidal bonding arrangement

  • square pyramidal
  • square planar
  • octahedral
A

trigonal bipyramidal = PCl5
- 5 electron domains, 5 bonding electrons

square pyramidal = BrF5
- 6 electron domains, 5 bonding electrons, 1 lone pair of electrons

square planar
- 6 electron domains, 4 bonding electrons, 2 lone pair of electrons

octahedral = SF6
- 6 electron domains, 6 bonding electrons