Projectile Motion

Question 1

 Along x, thre is

Answer 1

uniform motion

Question 2

uniform motion along x axis, so a =

Answer 2

0

Question 3

 Along y there is

Answer 3

uniformly accelerated motion

Question 4

since y has uniformly accelerated motion, a =

Answer 4

-g

Question 5

assumption in projectile motion is:

Answer 5

negligible air resistance

Question 6

vox=

Answer 6

vo cos⁡ϴ

Question 7

voy=

Answer 7

vo sin⁡ϴ

Question 8

Horizontal component of initial velocity:

Answer 8

vox= vo cos⁡ϴ

Question 9

Vertical component of initial velocity:

Answer 9

voy=vo sin⁡ϴ

Question 10

Vertical component of initial velocity:

Answer 10

voy=vo sin⁡ϴ

Question 11

Velocity at any time t (same velocity along x):

Answer 11

vx= vox=vo cos⁡ϴ

Question 12

Velocity at any time t (accelerated motion along y)

Answer 12

v_y= v_o sin⁡ϴ+at

Question 13

To find position of projectile at any time t (x)

Answer 13

x= vx t=(vo cos⁡ϴ)t

Question 14

To find position of projectile at any time t (y)

Answer 14

y= voy t+1/2 at^2

Question 15

For total time of flight

Answer 15

(2vo sin⁡ϴ)/g

Question 16

Range = maximum x

Answer 16

R= (vo^2 sin⁡2ϴ)/g

Question 17

the time at maximum height is equal to one-half of the total time of flight:

Answer 17

t(1/2)=(vo sin⁡ϴ)/g

Question 18

Find Ymax (maximum height)

Answer 18

ymax=((vo^2 sin^2⁡ϴ ))/2g

Question 19

when a body is given an initial velocity in the horizontal directional only

Answer 19

horizontal projection

Question 20

for horizontal projection Vo =

Answer 20

0

Question 21

horizontal projection

Vy =

Answer 21

-gt

Question 22

y =

Answer 22

vot + 1/2at^2

Question 23

total time of flight in horizontal projection

Answer 23

√2y/g

Question 24

xmax in horizontal projection

Answer 24

Vo√2y/g