9.4.3 The Fundamental Theorem of Calculus, Part I Flashcards
The Fundamental Theorem of Calculus, Part I
- Understand The Fundamental Theorem of Calculus, Part I, which links areas under curves with derivatives.
- Apply The Fundamental Theorem of Calculus, Part I to differentiate a complicated function defined by an integral.
note
- The Fundamental Theorem of Calculus, Part I states that if a function f(x) is continuous on a closed interval [a, b] and then F(x) is continuous and differentiable on [a, b], and F´(x) = f(x).
- The Fundamental Theorem of Calculus is the fundamental link between areas under curves and derivatives of functions.
- This example demonstrates the power of The Fundamental Theorem of Calculus, Part I. To differentiate the given complicated function F(x) directly requires first performing the integration, which itself requires a u substitution. Once integrated, taking the derivative requires using the Chain Rule.
- All of this can be bypassed by using The Fundamental Theorem of Calculus, Part I. The derivative of the given
function is simply the integrand evaluated at x.
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x) = ∫^x t+1/t-1 dt, [1,5]
F’(x) = is not defined over all of [1,5]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫ x100 cost/√t−99 dt, [100,200]
F′(x)=cosx/√x−99 on [100,200]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x17 cost/√t−17 dt, [17,40]
F′(x) is not defined over all of [17,40]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x−2f(t)dt,[−2,2],where f is continuous on [−2,2].
F′(x)=f(x) on [−2,2]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x2 5t^−1e^t dt, [2,8]
F′(x)=5x^−1e^x on [2,8]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x−5 4t^−1 dt,[−5,−1]
None of the above
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x1 lnt/t dt,[1,4]
F′(x)=lnx/x on [1,4]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x−3 (−4t^2+3t^−1 −7) dt,[−3,7]
F′(x) is not defined over all of [−3,7]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x0 sint dt,[0,2π]
F′(x)=sinx on [0,2π]
Use the Fundamental Theorem of Calculus to find an expression for the derivative of the given function defined on the given interval, if it exists.
F(x)=∫x1 3dt, [1,1000]
F′(x)=3 on [1,1000]