9.2.2 Integrating Polynomials by Substitution Flashcards
1
Q
Integrating Polynomials by Substitution
A
- The differential of an integral identifies the variable of integration.
- Integration by substitution is a technique for finding the antiderivative of a composite function. To integrate by substitution, select an expression for u. Next, rewrite the integral in terms of u. Then simplify the integral and evaluate.
2
Q
note
A
- When using Leibniz notation, the expression underneath the bar indicates the variable with respect to which the derivative is taken.
- The same expression appears when working with integrals. Integrate with respect to the variable indicated by this expression.
- Notice that the integrand is the product of a composite function and the derivative of its inside. The presence of a composite function is a sign that you should try integration by substitution.
- As with derivatives, the integral of a product of two functions is not equal to the product of the integrals. Find a way to transform the integral into something you can evaluate.
- Here, let u be the inside of the composite function.
- Notice that the derivative of u is contained within the
integrand. - Substitute so that you remove all of the x-terms from the integrand. The resulting integral is one you can evaluate with the power rule. This is how you integrate by substituting.
- Do not forget the constant of integration.
- When using integration by substitution, always express the answer in terms of the original variable.
3
Q
Integrate.∫^3√x−1dx
A
(x−1)^4/3 / 4/3 + C
4
Q
Solve the following integral:∫2x^2(x^3+3)^3/2dx.
A
4/15(x^3+3)^5/2+C
5
Q
Evaluate.∫x^4√7+x^5dx
A
2(7+x^5)^3/2 / 15+C
6
Q
∫x^3(x^4−1)^5dx.
A
(x^4−1)^6 / 24+C
7
Q
Evaluate:∫(2x+2)(x^2+2x+1)^3dx.
A
(x^2+2x+1)^4/4+C
8
Q
Evaluate:∫√1−xdx.
A
-(1−x)^3/2/ 3/2+C
9
Q
Integrate.∫9dp(3p−1)^3
A
−3/2(3p−1)−2+C
10
Q
Solve the integral.∫2y(3y^2−5)^1.7dy
A
(3y^2−5)^2.7 / 8.1+C
11
Q
Evaluate the integral:∫x^6√(x^2+1)^5dx
A
3/11(x^2+1)^11/6 +C
12
Q
Evaluate the integral.∫2(x+1)^5dx
A
−1/2(x+1)^4+C