6.7.2 Hyperbolic Identities Flashcards
Hyperbolic Identities
- When verifying a hyperbolic identity, use the definitions of the hyperbolic functions.
- The hyperbolic identities mirror many of the trigonometric identities.
- The hyperbolic functions are derived from a hyperbola like, the trig functions are derived from a circle.
note
- Verify this hyperbolic identity by substituting the defining expressions of cosh x and sinh x.
- Since the numerators are binomials, you need to square them using FOIL or the distributive property. A classic mistake is to square just the terms of each binomial.
- After combining terms and canceling, you can verify that the left-hand side of the identity equals the right-hand side.
- On the left, substituting X and Y for cos 2 x and sin 2 x illustrates their relationship to a circle.
- Similarly, on the right, substituting X and Y for cosh 2 x and sinh 2 x illustrates their relationship to a hyperbola. Hence, this is where the name hyperbolic function comes from.
Which of the following is not equivalent to
3 (1 + sinh^2 x)?
3+3(e^2x+2+e^−2x)/4
Which of the following is not an identity?
e^2x/2+e^−2x/2=2sinh^2x
You know that cosh x=e^x+e^−x/2.
Which of the following is the expansion of
cosh2 x ?
e^2x+2+e^−2x/4
Which of the following statements related to hyperbolic functions is not correct?
cosh2 x − sinh2 x = cos2 x − sin2 x for all x.
Use x and y to represent cosh t and sinh t, respectively.
Which of these graphs represents
cosh^2 t − sinh^2 t = 1?
Let x = cosh t and y = sinh t. cosh2 t − sinh2 t = 1 x 2 − y 2 = 1 For x = 1, y = 0. For x = −1, y = 0. For −1 < x < 1, there are no corresponding y-values. The graph is a hyperbola.
Expand 2 sinh x cosh x.
2sinhxcoshx=e^2x−e^−2x/2=sinh2x
You know that cosh2 x − sinh2 x = 1. Using this identity, which of the following is equivalent to coth2 x ?
csch2 x + 1
You know that cosh2 x − sinh2 x = 1. Using this identity, which of the following is equivalent to tanh2 x ?
1 − sech2 x
Which of the following is equivalent to e^2x+2+e^−2x/2 −2?
2 sinh2 x
Expand (e^x−e^−x/2)^2
(1/4)(e^2x−2+e^−2x)