12.3.1 The First Type of Improper Integral Flashcards

1
Q

The First Type of Improper Integral

A

An improper integral is a definite integral with one of the following properties: the integration takes place over an infinite interval, or the integrand is undefined at a point within the interval of integration.
• With some improper integrals, the area of the region under the curve is finite even though the region extends to infinity.
• An improper integral that is infinite diverges. An improper integral that equals a numerical value converges.

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2
Q

note

A
  • A definite integral is considered an improper integral if it has one of these properties:
    · the integration is over an infinite interval; or
    · its integrand is undefined at a point within the
    interval of integration.
  • Imagine calculating the area of the region under the curve y=1/x^2, starting at x = 1 and moving to the right. You would integrate the function from 1 to ∞ and solve the improper integral. The solution of the integral is one. This means that the area under the curve to the right of x = 1 has an area of one. You can think about this area “repackaged” into the square bounded by the origin and the point (1,1). Because this improper integral has a finite value, it converges.
  • An improper integral diverges if its value is infinite. Imagine calculating the area under the curve y=1/x
    , starting at x = 1 and moving to the right. You would integrate the function from 1 to and solve the improper integral. In this example, the value of the integral is infinity, meaning that the area under the curve is infinitely large. This improper integral diverges.
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3
Q

Evaluate ∫∞ 25 250,000/x^3dx.

A

200

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4
Q

Which of the following best describes the red region under the curve for y = 1 / x^ 2?

A

The red region is dropping in height as x increases. As a result, the change in the area decreases as x increases

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5
Q

Which of the following statements correctly describes improper integrals?

A

An improper integral that has a defined numerical value converges. Otherwise the improper integral diverges.

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6
Q

Evaluate ∫∞ 1 1/√x dx

A

The improper integral diverges.

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7
Q

Which of the following is not an improper integral?

A

∫−2 0 x dx

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8
Q

Which of the following statements is true for

∫ ∞ 0 e^−x dx?

A

The integral is improper and converges to 1.

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9
Q

Evaluate ∫ ∞ 0 cosx dx.

A

The improper integral diverges.

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10
Q

Which of the following best explains why these two improper integrals differ from one another?
∫∞11x2dx∫∞11xdxImproper Integral A Improper Integral B

A

Improper Integral A is convergent because it approaches a value of 1.
Improper Integral B is divergent because it approaches infinity.

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