7.2.2 Using the Tangent Line Approximation Formula Flashcards
Using the Tangent Line Approximation Formula
• The tangent line approximation formula is f(x+delta x) = f(x) + f’(x)(delta x)
note
- The process of finding a linear approximation can be
described by a general formula. - When making a linear approximation, you start by finding the equation of the line tangent to the curve at an “easy point.” A point is considered easy if you can evaluate the function at that point. For example, the square root function is easy to evaluate at the number 9.
- The distance between the easy point and the point you are interested in is the change in x, or x.
- Use the point-slope form of a line. Notice that the slope of the tangent line is equal to the first derivative of the curve evaluated at the “easy point.”
- The y-value of this equation tells you the height of the line at that x-point. Remember, this y-value is a good
approximation for the function at that point. This equation is called the tangent line approximation formula. - To use the tangent line approximation formula, start by finding a good easy point and the distance between the easy point and the point you want to approximate.
- In this example you are asked to approximate the value of the cube root of 7.9. Since you know that the cube root of 8 is 2, you can use that point as your easy point. The signed distance between 8 and 7.9 is –0.1.
- Find the derivative of the cube root function using the power rule. Evaluate the derivative at the “easy point.” Finally, plug all of that information into the linear approximation formula.
- The resulting approximation is accurate to 4 decimal places.
Use the linear approximation formula to approximate e^2.1.
e^2.1≈11e^2/10
Use the linear approximation formula to approximate 3√7.9.
√7.9≈239/120
Use the linear approximation formula to approximate ln 1.1.
ln1.1≈1/10
Find the linearization of the function f(x)=√x+8 at a=1.
y=x/6+17/6
What is the largest interval of x for which the linear approximation √1+x≈1+x/2 is accurate to within .2?
(.4−√1.6,.4+√1.6)
Use the linear approximation formula to approximate
3√27.1.
√27.1≈811/270
Use the linear approximation formula to approximate e^3.1.
e3.1≈11e^3/10
Use the linear approximation formula to approximate sec 99π/100
sec99π/100≈−1
Use the linear approximation formula to approximate √16.2.
√16.2≈161/40
Use the linear approximation formula to approximate the root.
√3.9
√3.9≈79/40
Use the linear approximation formula to approximate tan 0.1.
tan.1≈0.1
Use the linear approximation formula to approximate √15.9.
√15.9≈319/80