6.3.5 Finding the Inverse of a Function Flashcards

1
Q

Finding the Inverse of a Function

A
  • To determine the inverse of a function algebraically, swap the independent variable (x) and the dependent variable (y) and then solve for y.
  • Verify the inverse by composing it with the original function as described in the definition of an inverse.
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2
Q

note

A
  • To find the inverse of a function graphically, you
    reflect the curve of the function across the line given
    by y = x.
  • This reflection just swaps the roles of y and x.
  • To find the inverse of a function algebraically, first
    rename the function y. Then swap y and the
    independent variable, which is usually x.
  • Solve for y to get an expression for the inverse
    function.
  • Since the original function is f ( x ), the inverse is
    noted as f^-1( x ).
  • In order for two functions to be inverses of each
    other, all roads must lead to x.
  • Evaluate the compositions f ( f^-1( x ) ) and f^-1( f ( x ) )
    to make sure they both equal x. You must check
    both directions.
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3
Q

Which of the following correctly relates the process of algebraically finding the inverse of a function f (x)?

A

To find the inverse of a function, first rename the function y, then swap y and x, and solve for y to get an expression. If both f −1 ( f (x)) = x and f ( f −1 (x)) = x, this expression is f −1 (x).

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4
Q

Given f (x) = e^x + 2x, which of the following is

f −1 (1)?

A

0

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5
Q

Given f(x)=2x+3/x−1, find f−1(x).

A

f−1(x)=x+3/x−2

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6
Q

Given f(x)=1/x+2+5, where x≠−2,find f−1(x).

A

f−1(x)=1/x−5 −2

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7
Q

To find the inverse of a one-to-one function f (x) graphically, reflect the function’s graph over ____________________.

A

y=x

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8
Q

Given f (x) = 4x^ 5 + 1, find f −1 (x).

A

f−1(x)=5√x−1/4

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9
Q

Given f (x) = x ^2, for x > 0, find f −1 (x).

A

f−1(x)=√x

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10
Q

Given ln(x−1)/3, find f−1(x).

A

f −1 (x) = e ^3x + 1

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11
Q

Given f (x) = ln (x^ 3 ), find f −1 (x).

A

f −1 (x) = e^ x / 3

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12
Q

Given f (x) = 2e ^3x + 8, find f −1 (x).

A

f−1(x)=1/3ln(x−8/2)

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