2.2.1 Evaluating Limits Flashcards
Evaluating Limits
- The limit of a function is the range value that the function approaches as you get closer to a particular domain value.
- To evaluate a limit at a value where a function is well behaved, substitute the value into the function expression.
- Limits that produce indeterminate forms may or may not exist. An indeterminate form is a signal that more work is needed to evaluate the limit.
limit
- Limits allow you to study the behavior of a function near a certain x-value. If the function approaches the same value on either side of that x-value, then the limit exists.
- This limit is read as “the limit as x approaches 5 of f of x.”
- You can evaluate limits of well behaved functions by substituting the x-value into the limit expression.
- Notice that the value of the function given by y = 2x + 1 at x = 3 is the same as the limit as x approaches 3 of 2x + 1.
indeterminate form
- For some limits, direct substitution will result in an indeterminate form such as 0/0. This expression cannot be evaluated since division by 0 is not defined.
- An indeterminate form is a sign that you need to do more work.
- In this case, you can factor the expression and cancel the x in the numerator with the x in the denominator. You can then substitute 0 in for each occurrence of x and determine the value of the limit. This limit is 1, which agrees with the graph of the function.
- When you cancel you have to promise that the denominator will never be 0. However, the limit is studying the function near x = 0 and not at that value. Therefore direct substitution is allowed.
Evaluate lim x→2 2x.
4
Which of the following sets represents all of the possible removable discontinuities of the function f (x) = x^ 3 + 3x^ 2 + 2x / x^ 3 + x ^2 − 2x?
(The sets represent x-values)
{−2, 0}
Let f and g be continuous at a. Which of the following functions is not necessarily continuous at a ?
f∘g
Suppose you are evaluating the limit lim x→5 f(x) and plugging in x=5 results in the expression 00.In this case, the value of lim x→5f(x) is:
There is not enough information.
Evaluate.lim t→4 13t−52/2t−8
13/2
Expressions of the form 0/0 are known as:
Indeterminate forms
Evaluate lim x→−2 (4x^2+1).
17
Consider the function
f(x)=x^3+x/x .
Is f (x) continuous at x = 0?
No, f (x) is not continuous at x = 0.
Evaluate.
lim x→0 (5x^3−5x^2+5−e^x)
4
Gary is simplifying the expression for a function f (x).
What is wrong with his work?
f(x)=x^2−5x+6/3x−6 = (x−2)(x−3)/3(x−2) = x−3/3
Therefore, Gary concludes,
f(x)=x−3/3.
Gary has to note that x cannot equal 2 using his simplified expression.
Evaluate.lim s→2 4s^2−4s+2
3
Consider the piecewise function f(x)={|x|, x≠0 0, x=0 . Is f(x) continuous at x=0?
Yes, the function is continuous at x = 0.