9.3.1 Integrating Composite Trigonometric Functions by Substitution Flashcards
1
Q
Integrating Composite Trigonometric Functions by Substitution
A
- Integration by substitution is a technique for finding the antiderivative of a composite function. A composite function is a function that results from first applying one function, then another.
- If the du-expression is only off by a constant multiple, you can still use integration by substitution by moving that constant out of the integral.
2
Q
note
A
- This integral involves a composite function: the sine of a complicated expression. If you let u be the inside of the function, notice that du is found surrounding the sine function.
- After you substitute u, make sure that nothing remains in terms of x.
- Recall that the derivative of –cosx is sinx.
- Make sure to replace u with its expression in terms of x.
- You can check that your answer is correct by taking its
derivative. - Here is another composite function. Let u be the inside
expression. When you find du, you will notice that there is no multiple of 4 in the integrand, just dx. - Since 4 is just a constant multiple, solve for dx and substitute that expression into the integrand.
- You can move 1/4 outside the integrand since it is a constant multiple.
- After you integrate, make sure to replace u with its expression in terms of x.
- Take the derivative of your answer to make sure it is correct.
3
Q
Solve the integral:∫x^−1/4 csc^2x^3/4dx
A
−4/3cotx^3/4+C
4
Q
Integrate:∫3x^2sinx^3dx
A
− cos (x ^3 ) + C
5
Q
Integrate.∫2t(1+t^2)^2sec^2[(1+t^2)^3]dt
A
1/3tan[(1+t^2)^3]+C
6
Q
Find the integral.∫5xcosx^2dx
A
5/2sin x^2+C
7
Q
Evaluate:∫2x^3sinx^4dx.
A
−1/2cosx^4+C
8
Q
Evaluate the integral.
∫cos√x/√x dx
A
2sin√x+C
9
Q
Integrate:∫xsec^2(x^2−1)dx.
A
1/2tan(x^2−1)+C
10
Q
Evaluate:∫√x cscx^3/2 cotx^3/2dx
A
−2/3cscx^3/2+C
11
Q
Evaluate the integral:∫^3√x⋅sec^2(1−x^4/3)dx
A
−3/4tan(1−x^4/3)+C
12
Q
Solve the integral.∫(sec2xtan2x) dx
A
sec2x/2+C