Work Problems Flashcards
Work
Rate*Time
The rate at which an object is performing a task or job can be expressed as
Work/Time
3 types of rate problems
1) A specific quantity of work completed in a specific amount of time -> 12 cars per month
2) The work as a single job or task completed in a specific amount of time -> 1/4 pool/hour
3) An object completes a fractional amount of work in a specific amount of time -> 3/8 gallon/hour
Matrix for solving work problems
Rate * Time = Work
Object Working
Single worker problems
Typically, we are asked to either find the rate at which an object works, the time the objects spends working, or the amount of work performed by an object
Combined worker problems
When two or more object work together
-> Work (object 1) +Work (object 2)= Work total
Two objects work together at the same time
In your table, make the time the same and work from there -> so the time will be x(or same #)
Two objects being a job together, but one object stops before completion
1) Let the work time for the object that stops first be represented by x
2) Let the work time for the object that finishes the job alone be represented by (x+y) with y representing the additional time needed to complete the job
Two object work together, but one object has an unknown time
1) we can represent the rate at which it can complete the job as 1/t where 1 represents 1 job (work) and the variable t presents the time it takes to do that job
* * If the job being done is more or less than 1 job, we need to account for the numerator
- -> if john can drink 100 sodas in an unknown time, his rate can be expressed as 100/t
Percent of a job done and fraction of a job done
- Assume that you both worked the same amount of time
1) Determine the total work that is performed (since you both work for the same time, let’s let the work time be t)
2) Work you do/Work total
Opposing worker problems
Subtract the work done by one object from the work done by the other object; the work of one retards, reduces the work of the other
Rate of one worker is expresses as a multiple of the rate of another worker
- > Tom can drink milk 4 times faster than Joe can drink milk
- > we can let Joe’s rate be some variable r and Tom’s rate be 4r to express the relationship
Rate of one worker is slower or faster than the rate of another worker
If object 1 takes x minutes longer than object 2 to complete a job and we let object 2’s time be represented by the variable t minute, object 1’s time would be (t+x) minutes. Then, object 1’s rate would be 1/(t+x) job minutes, and object 2’s rate would be 1/t job/minute
One worker can complete a job in some percent (or fraction) greater or less than the time it takes another worker to do the same job
1) If 1 takes x percent fewer minutes than object 2 to complete a job and we let object 2’s work time be t((100-x)/100) minutes.
2) Then, object 1’s rate would be 100/t(100-x) job minutes and object 2’s rate would be 1/t job/minute
Change in workers problems
what happens when workers in the group of workers to complete a task when a certain number of workers are added to or removed from a group
- In these problems we need to
1) Defining the rate of one worker
2) The proportion method
- In these problems we need to
- use proportion to solve these problems