Percentage Flashcards

1
Q

x%

A

x/100 (and we reduce the fraction if possible)

5%= 5/100 or 1/20

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2
Q

To convert a decimal or an integer to a percent

A

multiply the decimal or integer by 100 and attach the percent sign

0.03*100= 3%

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3
Q

To convert a fraction to a percent

A

multiply the fraction by 100 and attach the percent sign

7/100 -> (7/100)*100= 7%

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4
Q

To convert a percent to a decimal

A

drop the percent sign and divide by 100 drops the percent sign and divide by 100

5/10= 0.5

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5
Q

When we need to find a percent of an unknown amount, we can either

A

1) represent the unknown amount by a variable, such as x

2) Assume the unknown amount is 100 items

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6
Q

Percent word problems

A

1) “Percent of”
2) “What percent”
3) “Percent less than”
4) “Percent greater than”
5) “Percent change”

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7
Q

Percent of represents

A

multiplication of a given number

i.e: 5 percent ofz= 5/100 (z)= z/20

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8
Q

What percent

A

we can translate “what percent” into x/100, and then set up an equation to solve for “x.”

  • > 20 is what percent of 80 can be solved using the (a/b)100 = (20/80)100
  • > this method will either yield a decimal or integer unless we multiply the quotient
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9
Q

We may encounter percent problems in which the percents given are variables.

A

For example, “p percent of q is equal to r.” We can translate this to p100×q=r, or “a percent of b is equal to c.” We can translate this to a100×b=c.

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10
Q

Percent less than Problems

A
  • ## “Percent less than” problems relate to a reduction in the value of something
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11
Q

Percent less than Problems: Reduction

A

(InitialValue)×(1−”PercentLessThan”/100).

-The initial value is the value of an item before its value is reduced, and the final value of an item is the value after the reduction has occurred.

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12
Q

“Percent greater than” problems

A
  • “Percent greater than” problems relate to the increase in value of something.
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13
Q

“Percent greater than” problems equation

A

⇒FinalValue *(InitialValue)×(1+PercentGreaterThan/100)

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14
Q

In “Percent Greater Than” problems

A

x% greater than y is equivalent to (100 + x)% of y

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15
Q

100 percent greater than z

A

200 percent of z

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16
Q

450 percent greater than z

A

550 percent of z

17
Q

Markup by P percent:

A

$1,000×(1+P/100)

18
Q

Markdown by P percent:

A

$1,000(1−P/100)

19
Q

Successive percent changes

A

goes through mutiple changes -> up, down,up,up and so on

-> Successive percent changes should be multiplied.Successive percent changes should be multiplied.

20
Q

an item that initially cost $100 was marked up 20 percent and that the resulting value was then increased 20 percent more.

A

($100×120/100)×120/100=$144.

21
Q

What if we took another $100 item, marked it down 20 percent, and then marked the resulting value down 20 percent more?

A

($100×80/100)×80/100=$64.

22
Q

“Percent change” problems

A
  • increase or decrease in a value after a change in that value has occurred
23
Q

$800 is what percent greater than $100?

A

The final price may be 8 times the starting price, but the stock’s final value is only 700 percent greater than its initial value.

24
Q

Percent Change

A

(FinalValue−Initial Value)/InitialValue)×100

25
Q

Final Value (Increase)

A

(InitialValue)×(1+PercentGreaterThan100)

26
Q

Final Value (decrease)

A

(InitialValue)×((1−PercentLessThan)/100)

27
Q

The Value of an Item Decreases Then Returns to Its Original Value.

A

To return a discounted value back to the original value, we must increase the discounted value by some percent greater than the percent by which it was discounted.
-> To determine the percent by which we must increase a discounted value to return it back to its original value, we can use the percent change formula:

28
Q

Profit

A

Revenue- Cost

29
Q

%Profit

A

profit/cost×100