Inequalities Flashcards
Open circle in inequalities
will not include that variable but includes other than that
Close circle in inequalities
will include that variable and other variables including that
When you divide or multiply by a negative number
the inequality must change the sign
In order to add/subtract and equalize something in the equalities, they have to be
facing the same sign
Example:
-x+7y > 26
-7y+2x > -12
When we are multiplying or dividing by a variable
if the sign of the variable is unknown, we cannot know whether to rotate the inequality sign
-> so we should never multiply or divide an inequality by a variable unless the signs of the variable is known
Compound inequality: a
You have to do it to all the sides
a a-5 < x+5-5 a-5 < x< b-5
When comparing the relative size of the variables expressed in multiple inequalities
consider setting up a number line to compare the values graphically
What is the possible value of
x^2>b
x < -sqrt(b)
x > sqrt(b)
If a <= x <=b and
c <= y <= d , find the maximum value of xy
we evaluate the following four quantities ac, ad, bc and bd. The largest of the four values will be the maximum and the smallest one will be the minimum of xy
For any real numbers a, if a => 0, |a| =
a
For any real numbers a, if a <= 0, |a| =
-a
We know that the absolute value mask the true value inside the bars could be positive or negative
thus the value inside the bars can be positive or negative
-> so we need to solve the equation twice -> first one where the value is post
Equation that contain absolute value
we must isolate those absolute value bars and perform the work outside them prior to splitting the equation i.e : 5 |2x-1| -5 = 20 = 5 |2x-1|= 25 = |2x-1|= 5 = 2x-1 = -5 and 2x-1 = 5
|5| = |5| and
|-5| = |-5|
|a+b|
<= |a|+|b|
If a and b are non-zero number and |a+b| = |a| + |b| then a and b must have
same sign
-> either both negative or both positive
|a-b| >=
|a|-|b|
If p and q are non-zero number and |p-q| = |p| - |q| then
1) pq > 0 (says that not have to be the same sign)
2) p’s distance from zero on the # line is greater than q’s distance from zero on the # line –> so the number itself should be bigger
or. ..
1) the second quantity is 0
Can you see the similarity between x^2 > 4 and |x| >4
yes two answers
If the absolute value of an expression is equal to a negative number
there is no solutions to that equation
|x+1| = -2 -> can’t have this
If an absolute value has a variable on both sides of the equation, we must
check the solutions of the equations for the extraneous solutions
-> extraneous variable is one that appears to be the solution but is not
If |6x+14| = |8x+6| then what is the product of all possible values of x
You can get all the possible values by solving these two
A. Equal: |6x+14| = |8x+6|
B. Opposite: |6x+14| = -|8x+6|
0 is a multiple of
all numbers
ab > ac
two possibilities for ab and ac, depending on what the sign of a is
1) b> c
2) b