Proteins And Enzymes Flashcards

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1
Q

Structure of an amino acid

A

H2N-CHR-COOH
NH2 = amine group
R = variable side chain. Can be:
- positive
- negative
- hydrophobic
- hydrophilic
COOH = carboxylic acid group

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2
Q

Describe how a dipeptide is formed

A

Condensation reaction
Produces peptide bond
OH from carboxylic group combines with H from amine group in second amino acid
Water produced

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3
Q

Describe the structure of proteins

A

Polymer of amino acids
Joined by peptide bonds
Formed by condensation reaction
Primary structure is number and order of amino acids
- Secondary structure is folding of polypeptide chain into alpha helix and beta pleated sheets due to Hydrogen bonding
- tertiary structure is 3D shape due to hydrogen bonds and ionic bonds and disulfide bridges
- quaternary structure is 2 or more polypeptide chains joined together

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4
Q

Describe how an enzyme substrate complex increases the rate of reaction

A
  • reduces activation energy
  • due to bending bonds
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5
Q

When a pathogen causes an infection, plasma cells secrete antibodies that destroy this pathogen .
Explain why these antibodies are only effective against a specific pathogen

A
  • Antigens have a specific tertiary structure
  • Antibody is complementary to antigen
  • antibody-antigen complex forms
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6
Q

Define activation energy

A

The minimum amount of energy required for a successful chemical reaction

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7
Q

How do enzymes increase the rate of the reaction

A
  • lowers activation energy
  • stressing/distorting bonds in substrate
  • during formation of enzyme-substrate complex
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8
Q

Describe how a change in the base sewuence of a DNA coding for an enzyme may result in a non functional protein

A
  • change in primary structure changes sequence of amino acids
  • hydrogen/ionic bonds and disulphide bonds form in different positions
  • alters the tertiary structure of the enzyme’s active site
  • no enzyme-substrate complexes can be formed
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9
Q

What is a proteome of a cell?

A

Full range of proteins a cell is able to produce

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10
Q

Describe and explain how you can use the bieuret test to distinguish a solution of lactase enzyme from a solution if lactose

A
  • add bieuret solution to both solutions.
  • Lactase enzyme = purple
  • because lactase is a protein
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11
Q

Sucrase doesnt hydrolyse lactose. Use your knowledge of the way in which enzymes work to explain why

A
  • lactose has a different shape
  • doesnt bind to the sucrase active site
  • substrate and active site are not complementary
  • No enzyme substrate complexes form
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12
Q

Describe the induced fit of enzyme action

A
  • active site not complementary
  • active site changes shape as substrate binds
  • distorts/stresses bonds within substrate
    -lowers activation energy
  • enzyme-substrate complex forms
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13
Q

Describe one way the lock and key model differs from the induced fit model

A

LAK: Active site doesnt change shape whereas IF: active site DOES change shape
- active site rigid vs flexible
- substrate is complementary to active site

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14
Q

An enzyme catalyses only one reaction. Explain why.

A

Enzymes active site has a specific tertisry structure
Only one substrate binds

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15
Q

Suggest why a protein can ve the substrate for two different enzymes

A
  • different parts of protein have different amino acif sequences so have different shapes
  • each enzyme active site is a specific shape and complementary to a different part of the protein
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16
Q

Diabetes mellitus is a disease that can lesd to an increase in blood glucose concentration. Some diabetics need insulin injections. Insulin is a protein so it cannot be taken orally. Suggest why insulin cab not ve taken orally.

A
  • broken down by enzymes
  • insulin no longer functional
17
Q

What is the effect of substrate concentration on the rate of an enzyme controlled reaction

A
  • increases then plateaus
  • plateaus because no active sites are available/all AS are filled
  • max number of enzyme-substrate complexes form per second
18
Q

Explain how a competitive inhibitor works

A
  • inhibitor similar shape to substrate
  • inhibitor enters active site
  • less substrate binds/ fewer ESC per second formed
19
Q

Describe how a non-competitive inhibitor works

A

Attaches to enzyme at allosteric site (site other than AS)
- changes shape of active site
- so active site no longer complementary to substrate
- less/no substrate binds and fewer ESC form

20
Q

Explain the results without inhibitor (curve A) shown in figure 6

A
  • increases because more ESC form
  • levels off because no free active sites
21
Q

Figure 6 shows that max initial rate of reaction when a competitive inhibitor was present ( curve B) is different from when a non-competitive inhibitor was present (curve C)

Explain this difference.

A
  • competitive inhibitor binds to active sites vs non competitive inhibitor binds to allosteric site
  • competitive inhibitor binding doesnt change shape of AS vs non competitice inhinitors do
  • with competitive inhibitor, high sub concentration = enzyme still available but non competigive at high sub conc = enzymes no longer available
  • at high sub conc, ES collisions likelihood increases with comp inhibitor but not possible with noncomp inhibitor
22
Q

describe how amino acids join to form a polypeptide so there is always a NH2 at one end and COOH at other.

A
  • . One NH2 group joins to a COOH group to form a peptide
    bond;
  • (So in chain) there is a free NH2 group
    at one end and a free COOH group
    at the other