L11 - enzyme substrate reactions Flashcards

1
Q

Why bother studying enzyme kinetics?

A
  • scientific reasons
  • clinical diagnostics
  • drug development
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2
Q

what are the scientific reasons?

A
  • enzyme kinetics (how fast reactions occur)
    = important for understanding biological (disease) processes
    = describes absorbance of drugs into cells by active transport
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3
Q

what is the clinical diagnostics importance?

A

clinical tests depend on measuring the activity of enzymes

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4
Q

what are the reasons behind the study of enzyme kinetics in drug development?

A
  • 50% of drugs used are enzyme inhibitors
  • kinetics tells us about the mechanisms of an enzyme reaction
    = allows determination of drug potency
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5
Q

what factors affect enzyme activity?

A
  • pH (inappropriate pH unfolds proteins)
  • denaturing reagents
  • temperature (high temp = high rate, until thermal denaturation)
  • activity is proportional to conc of enzyme
  • substrate conc
  • presence of inhibitors
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6
Q

how do enzymes work?

A
  • substrate binds to active site on enzyme
  • forms enzyme substrate complex
  • goes through catalysis
  • forms enzyme product complex
  • product unbinds, enzyme released
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7
Q

What is enzyme conc like compared to substrates? and why?

A

[E] &laquo_space;[S]
- because enzymes are catalysts

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8
Q

What do simple models assume?

A
  • 1 molecule of 1 substrate binds to enzyme
  • ES complex formed (rate-limiting step)
  • enzyme converts substrate to products
  • product binds weakly to enzyme
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9
Q

What are the units in the Michaelis-Menten curve?

A

v = rate
[S] = substrate conc
Vmax = rate when all enzyme active sites are occupied (saturated)
Km = [S] when v = 1/2Vmax

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10
Q

What is the equation for rate in the Michaelis-Menten curve?

A

v = Vmax[S]/Km + [S]

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11
Q

How to know when the reaction is first order with the MM eqn?

A

at low [S], rate (v) increases with increasing [S]

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12
Q

How to know when the reactions is zero order with the MM eqn?

A

at high [S], rate (v) doesn’t increase with further increases in [S]

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13
Q

what are the assumptions of steady-state model?

A
  • [E] &laquo_space;[S]
  • [S] remains constant
  • [ES] remains the same
  • product weakly binds weakly to enzyme
  • rate of conversion of product to substrate is negligible (no backward reaction)
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14
Q

What is method 1 of measuring Vmax and Km?

A

Michaelis-Menten plot

  • directly plot v against [S]
  • can be difficult to decide when Vmax is reached
    = requires a computer programme
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15
Q

What is method 2 of measuring Vmax and Km?

A

Lineweaver-Burk plot

  • plot 1/v against 1/[S]
  • y int = 1/Vmax, x int = -1/Km
  • higher precision, lower accuracy
  • errors are not equal at all points
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16
Q

What is method 3 of measuring Vmax and Km?

A

Direct linear plot

  • plot rate and substrate con onto axes
  • connect points
  • intersections are estimates of Km and Vmax
  • gives median value
  • no assumptions about errors
  • difficult to deviations from ideal behaviour
17
Q

What are the meaning of the kinetic parameters?

A

Km = conc of substrate at which v=0.5Vmax
- similar to substrate conc in cell

Vmax = max velocity = limiting rate

kcat = Vmax/amount of enzyme

18
Q

What is Km a measure off?

A

affinity of enzyme for substrate

19
Q

what is kcat?

A

first order rate constant for conversion of substrate to product