H2 and PPI med chem Flashcards

1
Q

how does the parietal cell work normally

A
  1. stimulated by ACh (M3), gastrin (CCK2), histamine (H2)
  2. invagination
  3. Leads to release of protons via H+ K+ ATPase into canaliculus
  4. Combine with Cl- (also released from parietal cell via Cl ion channel) to form HCL
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

how do H2 antagonists work to reduce stomach acid

A

H2 antagonists stop the binding of histamine to H2 receptor on parietal cell

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

natural histamine structure

A

imidazole ring - exists as 2 tautomers
aliphatic amine - charged at physiological pH

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

H1 agonist SAR

A

ring separated from positively charged N by 2C spacer
variation possible in aromatic ring

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

H2 agonist SAR

A

ring separated from positively charged N by 2C spacer
heteroaromatic ring must retain amidine group

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

H2 antagonist SAR

A
  • Ketoaminal group is optimal for binding
  • Sulphur group in chain increases activity
  • More hydrophobic ring reduces activity
  • Ring does not have to be imidazole!
  • Substitution pattern matters but groups can be changed
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

effect of cimetidine on CYP450

A

inhibitor!

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

proton pump MOA

A

Forms disulphide bond with one or more of three cysteine residues on proton pump- irreversible!

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

why can proton pump inhibitors be taken orally

A

not charged and lipophilic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

how are proton pump inhibitors activated

A
  1. PPI protonates benzimidazole ring
    1. Intramolecular reaction - 5 membered ring forms
    2. Benzimidazole ring reformed - formation of sulphonic acid derivative
    3. 2nd intramolecular reaction forms cationic pyrimidine
      Disulphide bond formed from thiol of proton pump - inhibited enzyme
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

omeorazole SAR

A
  • Substituents increasing basicity of pyridine ring = good
    • Methyl at meta are inductive
    • Methoxy are more effective at para then meta
    • Sulfoxide and pyridine N essential for activation
    • Ome in benzimidazole ring gives best balance of stability and potency
  • benzimidazole ring
How well did you know this?
1
Not at all
2
3
4
5
Perfectly