Transition Metals - Colours Flashcards
[Cu(H2O)6]2+ colour
pale blue solution
Cu(OH)2(H2O)4 + excess NH3
[Cu(NH3)4(H2O)2]2+ + 2H2O + 2OH-
dark blue solution
[Cr(H2O)6]3+ colour
violet solution
Cr(OH)3(H2O)3 + excess NH3
[Cr(NH3)6]3+ + 6H2O
purple solution
[Cu(H2O)6]2+ colour
pale blue solution
[Cu(H2O)6]2+ + 4Cl-
[CuCl4]2- + 6H2O
yellow
Structure of ethane-1,2-diamine ligand
H2NCH2CH2NH2
Structure of ethanedioate ligand
Has a charge of 2-.
3 ethanedioates can replace 6 H2Os.
How many coordinate bonds can EDTA form?
6 coordinate bonds.
Charge of 4-
How does V2O5 act as a catalyst in the contact process?
Allows sulfur dioxide to adsorb to surface.
Uses its variable oxidation states to provide an alternative reaction route.
[Fe(H2O)6]2+ colour
green solution
[Fe(H2O)6]3+ colour
yellow solution
[Mn(H2O)6]2+ colour
pink solution
[Cr(H2O)6]3+ colour
violet solution
[Fe(H2O)6]2+ + NaOH ->
Fe(OH)2(H2O)4 + 2H2O
green precipitate
[Cu(H2O)6]2+ + NaOH ->
Cu(OH)2(H2O)4 + 2H2O
blue precipitate
[Mn(H2O)6]2+ + NaOH ->
Mn(OH)2(H2O)4 + 2H2O
light brown precipitate
[Fe(H2O)6]3+ + NaOH ->
Fe(OH)3(H2O)3 + 3H2O
brown precipitate
[Cr(H2O)6]3+ + NaOH ->
Cr(OH)3(H2O)3 + 3H2O
grey-green precipitate
What forms when a metal-aqua ion, e.g. [Cu(H2O)6]2+, reacts with NaOH, and is the product soluble in water?
A metal hydroxide forms, e.g. Cu(OH)2(H2O)4 (s), which is a precipitate. It is insoluble in water.
What happens when iron (II) hydroxide, Fe(OH)2(H2O)4 (s), is exposed to air?
Precipitate turns green -> brown.
It is oxidised to Fe3+.
What happens when manganese (II) hydroxide, Mn(OH)2(H2O)4 (s), is exposed to air?
Precipitate turns brown -> darker brown.
It is oxidised to Mn3+.
What happens when we add excess NaOH to all of the metal hydroxides (precipitates) formed, except Cr(OH)3(H2O)3 (s)?
No change occurs.
What happens when we add excess NaOH to Cr(OH)3(H2O)3 (s)?
Grey-green precipitate dissolves.
Forms dark green solution.
What happens when we add excess NH3 to Cu(OH)2(H2O)4 (s)?
Cu(OH)2(H2O)4 (s) dissolves when excess NH3 is added.
Dark blue solution forms.
Ligand substitution reaction.
Cu(OH)2(H2O)4 (s) + 4NH3 -> [Cu(NH3)4(H2O)2]2+ +2H2O + 2OH-
What happens when we add excess NH3 to Cr(OH)3(H2O)3 (s)?
Cr(OH)3(H2O)3 (s) dissolves when excess NH3 is added.
Purple solution formed.
Ligand substituion reaction.