Page 28 Flashcards
How many steps are involved in the E1 reaction mechanism?
A: Two steps: formation of a carbocation and elimination of a β-proton.
How many steps are involved in the E1 reaction mechanism?
A: Two steps: formation of a carbocation and elimination of a β-proton.
What is the rate-determining step in an E1 mechanism?
A: The heterolysis of the C-I bond, forming the carbocation intermediate.
Q: What intermediate is formed during an E1 reaction?
A: A carbocation intermediate.
How does the leaving group behave in an E1 reaction?
A: The leaving group departs before the β-proton is removed.
What role does the base play in an E1 reaction?
A: It removes a β-proton from the carbon adjacent to the carbocation, forming a double bond.
How does an E1 mechanism differ from an E2 mechanism?
A: In E1, the reaction occurs in two steps with a carbocation intermediate, whereas in E2, the reaction occurs in one concerted step without an intermediate.
What type of kinetics does the E1 mechanism exhibit?
A: First-order kinetics.
Why is the carbocation step crucial in the E1 mechanism?
A: It determines the overall reaction rate and allows for potential rearrangements.
What is the key difference in timing between E1 and E2 reactions regarding the leaving group and proton removal?
A: In E1, the leaving group departs before the proton is removed, whereas in E2, both occur simultaneously.
Why is the E1 reaction favored in weak base conditions?
A: Because it relies on the stability of the carbocation rather than the strength of the base.
