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Question 1

How does the number of R groups on the carbon with the leaving group affect E2 reactions?

Answer 1

A: Increasing the number of R groups forms more highly substituted, stable alkenes, making the reaction faster.

Question 2

Why do tertiary alkyl halides react faster in E2 mechanisms compared to primary alkyl halides?

Answer 2

A: Tertiary alkyl halides form more substituted (and more stable) alkenes during the reaction, lowering the activation energy.

Question 3

Why do tertiary alkyl halides react faster in E2 mechanisms compared to primary alkyl halides?

Answer 3

A: Tertiary alkyl halides form more substituted (and more stable) alkenes during the reaction, lowering the activation energy.

Question 4

In E2 reactions, which product is more stable: a monosubstituted alkene or a disubstituted alkene?

Answer 4

A: The disubstituted alkene is more stable because it has greater substitution around the double bond, increasing stability through hyperconjugation and inductive effects.

Question 5

What happens in the elimination reaction of 1-bromobutane?

Answer 5

A: A primary alkyl halide (1-bromobutane) forms a monosubstituted alkene, which is less stable.

Question 6

What happens in the elimination reaction of 2-bromo-2-methylpropane?

Answer 6

A: A tertiary alkyl halide (2-bromo-2-methylpropane) forms a disubstituted alkene, which is more stable.