metal hydroxide precipitates, identifying anions (non-metal ions) + required practical Flashcards
describe how to use sodium hydroxide solution to identify calcium ions, magnesium ions and aluminium ions
how to distinguish between these three metal ions
If we add sodium hydroxide solution to these three solutions, then they all produce a white precipitate
That is a problem as we cannot distinguish between these three tests - and know which solutions contain which type of ions = They all produce a white precipitate
If we add excess sodium hydroxide solution, then the aluminium precipitate redissolves (this allows us to tell which of our three ions is aluminium - Al3+)
take original magnesium and calcium compounds
and perform a flame test .
We would need to do flame tests to work out which one is calcium.
In a flame test, calcium produces an orange-red flame.
This allows us to tell/know which compound is calcium and which one is magnesium
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take original magnesium and calcium compounds → flame
test,
calcium → (brick) red flame,
magnesium → no colour
Write balanced chemical equations for these sodium hydroxide precipitate tests - sodium, calcium and magnesium
calcium nitrate + sodium hydroxide -> sodium nitrate + calcium hydroxide
Ca(NO3)2 (aq)+ 2NaOH (aq) –> 2NaNO3 (aq) + Ca(OH)2 (s)
magnesium nitrate + magnesium hydroxide -> sodium nitrate + magneium hydroxide
aluminium nitrate + sodium hydroxide -> sodium nitrate + aluminium hydroxide
Al(NO3)3 (aq)+ 3NaOH (aq) –> 3NaNO3 (aq) + Al(OH)3 (s)
We are mixing calcium nitrate with sodium hydroxide solution - would also work for other soluble calcium compounds
products - sodium nitrate solution (solution because it is aq solution) and also insoluble metal hydroxide
We can tell that calcium hydroxide is a precipitate as it has the state symbol for a solid
insoluble metal hydroxides which form the precipitates
calcium hydroxide, mg(OH)2 , Al (OH)3
different ways to test for certain metal ions
flame tests
flame emission spectroscopy
we can also test for certain metal ions using their reaction with sodium hydroxide solution
What other metal ions can we use to test for using sodium hydroxide solution
Copper II ions react with sodium hydroxide to form a blue precipitate of copper (II) hydroxide
copper (II) nitrate + sodium hydroxide –>sodium nitrate + copper (II) hydroxide
Cu(NO3)2 (aq) + 2NaOH (aq)-> 2NaNO3 (aq)+ Cu(OH)2 (aq)
Iron (II) ions react with sodium hydroxide to form a green precipitate of iron (II) hydroxide
iron (II) nitrate + sodium hydroxide –>sodium nitrate + iron (II) hydroxide
Fe(NO3)2 (aq) + 2NaOH (aq)-> 2NaNO3 (aq)+ Fe(OH)2 (aq)
Iron (III) ions react with sodium hydroxide to form a brown precipitate of iron (III) hydroxide
Fe(NO3)3 (aq) + 3NaOH (aq)-> 3NaNO3 (aq)+ Fe(OH)3 (aq)
solutions of iron (III) ions - > add sodium hydroxide solution - brown precipitate of iron (III) hydroxide
describe how we can identify non-metal ions: CARBONATE
testing for the carbonate ion
- Add dilute acid to our sample
- If the carbonate ion is present then the acid will react with the carbonate to make carbon dioxide gas. We will see effervescence (fizzing). But That does not prove that we have carbon dioxide gas
- Bubble the gas through lime-water. If the lime-water goes cloudy, then this prove that we have carbon dioxide gas.
That means that we started with the carbonate ion
describe how we can identify non-metal ions: HALIDE - CHLORIDE
testing for chloride ions
- Add dilute nitric acid to the sample
- Add dilute silver nitrate solution
- Halide ions produce a precipitate of the silver halide. Each halide makes a different coloured precipitate
Chloride ions produce a white precipitate of silver chloride
describe how we can identify non-metal ions: HALIDE - BROMIDE
testing for bromide ions
- Add dilute nitric acid to the sample
- Add dilute silver nitrate solution
- Halide ions produce a precipitate of the silver halide. Each halide makes a different coloured precipitate
Bromide ions produce a cream precipitate of silver bromide
describe how we can identify non-metal ions: HALIDE - IODIDE
testing for iodide ions
- Add dilute nitric acid to the sample
- Add dilute silver nitrate solution
- Halide ions produce a precipitate of the silver halide. Each halide makes a different coloured precipitate
Iodide ions produce a yellow precipitate of silver iodide
describe how we can identify non-metal ions: SULFATE
testing for sulfate ions
- Add dilute hydrochloric acid to our sample
- Add barium chloride solution
- If sulfate ions are present, we will see a white precipitate of barium sulfate
A student adds dilute nitric acid and silver nitrate solution to an aqueous solution of a calcium halide
A white precipitate forms
Give the balanced symbol equation for this reaction
cgp page 157
CaCl2 + 2AgNO3 —> 2AgCl + Ca(NO3)2
CGP Page 161 Question 3.2
No the student is not correct.
The sample produced a white precipitate with hydrochloric acid and barium chloride solution, so he can be sure that it contains sulfate ions
Magnesium does produce a white precipitate with sodium hydroxide, but so do other metal ions - aluminium and calcium, so he cannot be sure that it contains magnesium ions
ionic equation for test for sulfates
Ba2+ (aq) + SO42- (aq) —> BaSO4 (s)
HCL is added to get ride of any traces of carbonate ions before you do the test
carbonate ions would also produce a precipitate so they would confuse the results
ionic equation for test for halides
Ag+ (aq) + Cl- —> AgCl(s)
Ag+ (aq) + Br- —> AgBr(s)
Ag+ (aq) + I- —> AgI (s)
ignore nitric acid
describe how to use chemical tests to identify the ions in unknown compounds - required practicals
compound A produces a lilac flame test
A sample of compound A was reacted with silver nitrate solution and dilute nitric acid. A yellow precipitate was formed
Explain your answer
Compound A produced a lilac flame test. That tells us that compound A contains the potassium ion
when compound A was reacted with nitric acid and silver nitrate solution it produced a yellow precipitate.
The silver nitrate test produced a yellow precipitate. This tells us that compound A contains the iodide ion
So compound A is potassium iodide
describe how to use chemical tests to identify the ions in unknown compounds - required practicals
compound B produced an orange-red flame test
A sample of compound B effervesced when tested with hydrochloric acid
The gas produced turned limewater cloudy
Identify compound B
Explain your answer
Compound B produced an orange-red flame test. That tells us that compound B contains calcium ion.
When compound B was reacted with an acid, it effervesced and the gas turned limewater cloudy
This tells us that compound B also contains the carbonate ion
So compound B is calcium carbonate