Lecture 9.24.14 (Ch.8 Enzyme Kinetics) Flashcards
Velocity of a reaction?
the quantity of S that disappear as P appear in a specific time
Equation for V?
V=k[S]
Second Order
keep 1 S at high concentrations & constant, while the other S is varied concentrations
(make look like its first order)
pseudo First Order
Second order that’s made to look like first order
Steady State Assumption
the more ES added the faster they will dissociate
therefore when the reaction is first started, there is a build up of [ES], but then [ES] becomes a steady state (constant)
[S] decrease while [P] increase, but the ES is the same
Vmax?
the theoretical maximal rate of reaction that is never reached
How can Vmax be reached?
require that ALL enzymes be tightly bound to substrate
Km?
the [S] at 1/2 Vmax
an estimate of the equilibrium constant for S binding to E (measure of the [S] required for effective catalysis to occur)
What does a small Km mean? high Km?
small: tight binding (better affinity)
high: weak binding
Kcat?
turn over # (how good E is at making P)
incorporates the rate constants for all the reactions between ES and E + P and gives a direct measure of the catalytic production of product under optimum conditions (saturated enzyme).
Kcat equation
Kcat=K2=Vmax/Etotal