Lab #19 Mendelian Inheritance Flashcards
Which of these is heterozygous?
AA
aa
Aa
All of these
Aa
Which of these is homozygous for the recessive allele?
AA
Aa
aa
All of these is correct
aa
Which of these is homozygous for the dominant allele?
AA
Aa
aa
All of these is correct
AA
The observed trait an individual has is called the:
Allele
Gene
Phenotype
Genotype
Phenotype
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers.
b. What is the phenotype of the mother?
Six fingers
Five fingers
Ff
ff
Six fingers
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers.
c. What are the genotypes of both parents?
Six fingers
FF
Ff
ff
Ff
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers. Set up the cross and use a punnet square to determine the genotypes and phenotypes of the children.
d. What is the probability of a 6 fingered child?
100% or 4/4
75% or 3/4
50% or 2/4
25% or 1/4
0% or 0/4
75% or 3/4
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers. Set up the cross and use a punnet square to determine the genotypes and phenotypes of the children.
d. What is the probability of a 6 fingered child?
100% or 4/4
75% or 3/4
50% or 2/4
25% or 1/4
0% or 0/4
75% or 3/4
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers.
a. What is the phenotype of the father?
Six fingers
Five fingers
Ff
FF
Six fingers
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers. Set up the cross and use a punnet square to determine the genotypes and phenotypes of the children.
e. What is the probability of a 5 fingered child?
100% or 4/4
75% or 3/4
50% or 2/4
25% or 1/4
0% or 0/4
25% or 1/4
In humans, six fingers (F) is the dominant trait; five fingers (f) is the recessive trait. If the father is heterozygous** for six fingers and the mother **has five fingers**, what is the probability of their **offspring having FIVE fingers?
Set up the cross and use a punnet square to determine the genotypes and phenotypes of the children.
100%
75%
50%
25%
1%
50%
In humans, six fingers (F) is the dominant trait; five (f) fingers is the recessive trait. If the father is heterozygous for six fingers and the mother has five fingers, what is the probability of their offspring having SIX fingers?
Set up the cross and use a punnet square to determine the genotypes and phenotypes of the children.
100%
75%
50%
25%
0%
50%
What is the name of the table (or square) used to calculate the probabilities of offspring genotypes?
Mendel
Genetic
Punnet
Darwin
Punnet
In humans, a type of blindness is due to a dominant allele and normal vision is the result of a recessive allele. Migraine headaches are due to a dominant, and normal is recessive. A male who is heterozygous for blindness does not suffer from headaches marries a woman who has normal vision and is heterozygous for migraines. What are the possible allele combinations in the gametes for the male and female?
Bb and mm for the males; bb and Mm for the female
Bb and mm for the female; bb and Mm for the male
Bm and bm for the male; bM and bm for the female
Bm and bm for the female; bM for the male
Bm and bm for the male; bM and bm for the female
In humans, a type of blindness is due to a dominant allele and normal vision is the result of a recessive allele. Migraine headaches are due to a dominant allele and normal (no headaches) is recessive. A male who is heterozygous for blindness and does not suffer from headaches marries a woman who has normal vision and is heterozygous for migraines. The punnet square has been started for you here:
What is the probability of having a child with normal vision who does not suffer from headaches?
0%
25%
50%
75%
100%
25%
In which type of inheritance is an intermediate phenotype observed.
Ex: Curly hair + Straight hair = Wavy hair (Wavy is the INTERMEDIATE condition between the two parents).
Co-Dominance
Complete Dominance
Incomplete Dominance
X-linked
Incomplete Dominance
For this question use W to represent the white allele and R to represent the red allele. In certain flowers, color is inherited by alleles that show incomplete dominance. In such flowers, a cross between a homozygous red flower (RR) and a homozygous white flower (WW) always results in a heterozygous pink flower (WR). Neither the red allele nor the white allele dominates but instead an intermediate phenotype is seen in the heterozygote. A cross is made between two pink flowers.
Set up the cross or use a punnet square to determine the genotypes and phenotypes of the offspring.
What is the probability of each of the colors (red, pink, and white) appearing in the offspring?
**Check all of the correct answers.**
Red 75%
Red 25%
Pink 50%
Pink 0%
White 100%
White 25%
Red 25%
Pink 50%
White 25%
For this question use W to represent the white allele and R to represent the red allele. In certain flowers, color is inherited by alleles that show incomplete dominance. In such flowers, a cross between a homozygous red flower (RR) and a homozygous white flower (WW) always results in a heterozygous pink flower (WR). Neither the red allele nor the white allele dominates but instead an intermediate phenotype is seen in the heterozygote.
A cross is made between a red flower and a pink flower.
Set up the cross or use a punnet square to determine the genotypes and phenotypes of the offspring.
What is the expected probability for various colors?
**Check all of the correct answers**
Red 100%
Red 50%
Pink 75%
Pink 50%
White 25%
White 0%
Red 50%
Pink 50%
White 0%
In humans, there are three alleles for blood type: A, B, and O. The allele for blood type A and the allele for blood type B show co-dominance. A person with both alleles has blood type AB. Both A and B dominant type O.
A man with alleles for blood types A and O marries a woman with alleles for blood types B and O. What are the phenotypes of the male and the female?
Male has type A blood; female has type O blood
Female has type A blood; male has type O blood
Female has type A blood; male has type B blood
Male has type A blood; female has type B blood
Female has type A blood; male has type B blood
In humans, there are three alleles for blood type: A, B, and O. The allele for blood type A and the allele for blood type B show co-dominance. A person with both alleles has blood type AB. Both A and B dominant type O.
A man with alleles for blood types A and O marries a woman with alleles for blood types B and O.
What is the probability of EACH blood type? (*Hint - They’re all the same!)
100&
75%
50%
25%
0%
25%
Which type of inheritance has 2 or more completely dominant alleles?
Ex: Parent 1 has blood type A + Parent 2 has blood type B = Child with blood type AB
Co-Dominance
Complete Dominance
Incomplete Dominance
X-linked
Co-Dominance
Which type of inheritance is affected by gender?
Co-Dominance
Complete Dominance
Incomplete Dominance
X-linked
X-linked
In humans, the condition for normal vision dominate color blindness; both alleles are linked to the X chromosome. A normal male marries a color-blind female. What is the genotype for the male and the genotype for the female?
XY for the male; XcXc for the female
XY for the female; XcXc for the male
XcY for the male; XcXc for the female
XcY for the female; XcXc for the male
XY for the male; XcXc for the female
In humans, the condition for normal vision dominate color blindness; both alleles are linked to the X chromosome. A normal male marries a color-blind female. If the couple has a daughter, what is the chance she will have normal vision?
What about the son?
The punnet square has been started for you. Complete the Punnet square to answer the question:
**Check all that apply**
Daughter - 100% chance normal
Daughter - 50% chance normal
Daughter - 0% chance normal
Son - 100% chance normal
Son - 50% chance normal
Son - 0% chance normal
Daughter 100% chance normal
Son 0% chance normal
The following genetics problem requires some detective work to determine the genotypes.
Normal pigmentation (A) dominates no pigmentation (albino 5 aa). Dark hair coloring (D) dominates light hair coloring (d). Two parents both with normal pigmentation, one with dark hair, and the other with light hair produce a child with dark hair and normal pigmentation (Child A), a child with light hair and normal pigmentation (Child B), and an albino child (Child C). Albinism is epistatic to hair color meaning that you can’t tell the real hair color because the albino genotype makes everyone’s hair white.
What are the genotypes for the parents? Determine the possible genotypes of the children first and use the information to figure out the parent’s genotypes. You cannot be sure of the children’s genotype for certain traits so write out all of the possibilities. Child A has been done for you as an example.
