Hardy-weinberg Equilibrium Flashcards
Allele frequency
Frequency of a particular allele in population.
-population fundamental unit of evolution
Genetic basis
For evolution to occur, genetic differences must account for phenotypic differences
Natural selection
Favors traits most adaptive under present environment (better foragers or better camoflouged or avoid predation)
Ever-changing environment
- individuals must MIGRATE, ADAPT, DIE
- natural selection acts on existing variations
- environment never creates favorable alleles
New alleles arisen by
Mutation and genetic drift , gene flow, nonrandom mating
Gene flow( when individuals disperse) alters allele frequency
Mutation
Changes in DNA base sequence
Genetic drift
Random changes in allele frequencies without regard to adaptation
Ex: elephant seals
Large population becomes small and increased to large
GENETIC BOTTLENECK: large-reduced-large)
-allele frequency is altered due to population crash
-small populations have big effect
-genetic drift inversely related to population size
Change in heritable characteristics
Consequence of change allele frequencies
-all evolutionary change is described as sequential origin of new alleles, their replacement of old ones and occasionally the origin of New through duplication or lateral transmission from another lineage leading to insertion. (By virus)
Hardy-Weinberg equilibrium
-situation where no evolution is occurring
-genetic equilibrium
-allele frequency will not change:
No natural selection
No mutation
No genetic drift (no infinte population size)
No allele flow
Random mating
-how a particular genotype will become more or less common over time
Phenotype frequency
Proportion of individual exhibiting observable traits
-#indiv with phenotype/ total
Genotype frequency
Proportion of genotypes at a given locus
-Indiv with genotype/ total
Allele frequency
Proportion of alleles at a given locus
-p= freq. dominant allele
-q= freq. recessive allele
Allele frequencies from number of individuals
- p= ((#AA + 1.5(#Aa))/ N
- q= ((#aa) + 1.5(#Aa))/N
N=total
Genotype freq. to allele freq.
P= f(AA) + 1.5(f(Aa))
q= f(aa) + 1.5 (f(Aa))
TO GO FROM ALLELE TO GENOTYPE MUST ASSUME HW EQUIL
Genotype to allele
AA= p^2
Aa=2pq
aa=q^2
P^2+2pq+q^2=1.0