Gene discovery and genetic mapping in eukaryotes Flashcards

1
Q

Describe forward genetic approaches

A
  • aim: to identify the sequence variation(s) responsible for a particular phenotype
  • phenotype -> sequence variation
  • requires no assumption
    about the function and the nature of the gene product
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2
Q

Describe reverse genetic approaches

A

aim: to identify phenotypic changes caused by a particular sequence variation
- sequence variation -> phenotype
- tests a hypothesis about the gene function

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3
Q

Describe the process of a forwards genetics approach

A
  • isolation of individual(s) with inheritable change of the phenotype of interest via mutagenesis/natural variation
  • identification of causative DNA variation(s)
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4
Q

Give some examples of natural variations

A

disease resistance, fur colour, herbicide tolerance

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5
Q

Describe induced variations

A
  • generated random mutations
  • chemical mutagens (point mutations, C to T or A to G)
  • UV- light ( point mutations)
  • X-rays or gamma rays (deletions)
  • transposable elements (insertions)
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6
Q

Give a chemical mutagen

A

Ethyl methane sulfonate (EMS)

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7
Q

List some methods to identify mutant genes in eukaryotes

A
  • insertion mutagenesis (Drosophila and plants)
  • linkage mapping + map-based cloning
  • whole genome sequencing
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8
Q

Describe insertion mutagenesis

A
  • transposons or Transposable Elements (TE) create mutations when they insert into genes
  • if the DNA sequence of the TE is know it can be used to identify and clone the mutant gene
  • molecular cloning methods can identify genomic DNA fragments containing TE
  • flanking DNA sequence encodes the gene of interest
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9
Q

Explain why onsertion mutagenesis is of limited utility

A
  • applicable only to a few well studied organisms
  • mutation efficiency is low
  • many induced or natural mutations are single- base substitutions
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10
Q

Describe mutation rate in Drosophila

A
  • new mutations at random sites about once every 150–300 kb
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11
Q

Describe linkage and recombination

A
  • linkage of genes in a linkage group was rarely absolute
    and produced recombinant progeny
  • different pairs of genes in a linkage group showed different but characteristic rates of recombinants
  • recombination frequency for a gene pair is related to the distance between these genes on the chromosome
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12
Q

Recombination frequency

A
  • the frequency of crossing-overs between two loci
  • (total number of recombination events / total number of gametes tested) x 100
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13
Q

Recombination events can be detected only in

A

gametes derived from a heterozygous parent

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14
Q

Describe linkage mapping

A
  • 1% recombination is sometimes called 1 Map Unit (MU) or 1 ‘centi Morgan’ (cM)
  • relative position of genes in a linkage group
  • generated from combining the recombination frequencies for multiple pairs of genes
  • a series of mapping steps can establish the map of a
    whole linkage group
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15
Q

Additive recombination frequencies

A

can exceed 50%

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16
Q

Describe genetic maps

A
  • often have multiple recombination events 1 per chromosome
  • as the physical distance increases, genetic distances (recombination frequencies) are under-estimated
  • good linearity of measured and additive recombination frequency between genes up to 25-30cM apart
  • tends towards the maximum 50% recombination frequency
17
Q

Genes near opposite ends of a chromosome are

A
  • effectively unlinked
  • exhibit ~50% recombination
18
Q

Linkage groups are established by combining

A

short-range linkages

19
Q

Describe the basics of the genetic map

A

based on recombination frequency (cMorgan)

20
Q

Describe the basics of the physical map

A

based on DNA sequence (base pairs)

21
Q

Although genetic maps and physical maps are

A
  • colinear (same gene order)
  • genetic map distances are often not the same as physical map distances
  • poor quantitative correlation
22
Q

Describe recombination rates across the chromosome

A
  • vary slightly
  • low near centromeres
  • ‘hot-spots’ and ‘cold-spots’ occur all along the chromosome
  • can be seen in whole-genome sequencing of 486
    recombinant lines of Arabidopsis thaliana
23
Q

Describe cross-over interference

A

one cross-over interferes with the coincident occurrence of another cross-over in the same pair of chromosomes

24
Q

How to identify the position of mutation with respect to classical and modern genetics?

A

Classical genetics: co-segregation of mutant phenotypes Modern genetics: co-segregation of the mutant phenotype with naturally occurring DNA polymorphisms (molecular markers)

25
Q

Describe molecular markers

A
  • a site of DNA polymorphism not associated with any observable phenotype, but can be detected with molecular techniques
  • reference points in the genome (can be used for mapping if different alleles are present in homozygote form in parents)
  • each sequence variation is an allele
  • naturally occurring variations
  • very numerous ( 10,000s per genome)
26
Q

How to generate a mapping population to measure genetic distance and position in the genome

A
  • Cross F1 heterozygous progenies
    or self-fertilise
  • F2: Select individuals with distinguishable homozygote phenotype
  • identify recombination events between gene of interest and molecular markers
27
Q

What do you need to generate a mapping population?

A
  • homozygous mutant
  • non-related individual with wild-type phenotype, which carries large number of sequence polymorphisms
28
Q

How do you know if a recombination event has occurred?

A

if the other parental allele of a linked marker appears in an homozygote mutant individual

29
Q

What is the problem with mapping by recombination frequency?

A

based on estimates of frequency: probabilistic

30
Q

Describe map-based cloning

A

maps the mutation relative to individual recombination events, rather than estimating recombination frequencies

31
Q

Describe mapping by sequencing

A
  • generate a mapping population
  • sequence DNA from the two parents and the bulked mapping population
  • genome sequence data identifies all mutated genes in this region
32
Q

How to generate a mapping population in mapping by sequencing

A
  • cross the homozygous mutant with an unrelated individual with high sequence polymorphism-> heterozygous F1 population
  • cross two F1s to generate F2 population
  • recombination between parental alleles occurs
  • select mapping population from F2 progeny and combine all individual into one sample, a ‘bulk’
33
Q

Causality is tested with

A

complementation

34
Q

Testing causality of a recessive mutation

A
  • introduce the wild-type (dominant) sequence of gene into the recessive mutant
  • if: WT; complementation -> mutation causes phenotype
  • if mutant-type; no complementation -> mutation does NOT cause phenotype
35
Q

Genetic distances are additive

A
  • over short distances only (owing to multiple cross-overs)
  • but allow linkage maps to be constructed.