Enzyme Kinetics Flashcards

1
Q

Catalyst:

A

substance that increases the rate of a chemical reaction without being consumed in the reaction

provides an alternative pathway for the reaction in which the rate-determining step has a lower Gibbs activation energy than that of the non-catalysed reaction

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2
Q

Catalysis

A
  1. Does not appear in the overall equation for the reaction although it may appear in the rate equation
  2. Some substances slow down chemical reactions and these are often called negative catalysts or inhibitors
  3. Does not affect the amount of product formedβ€”only the rate of its formation
  4. Small amount is usually needed
  5. Not changed chemically in the reaction and can be recovered at the end
  6. Sometimes may be changed physically
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3
Q

At a given temperature, the rate constant is greater for the catalysed reaction, so the reaction is ______

A

faster

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4
Q

Non-catalysed reaction proceeds through a _____ _______ state, whereas the mechanism for the catalysed reaction involves the formation of an intermediate

A

single transition

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5
Q

Enzyme-Catalysed reactions

A

Enzymes catalyse a wide range of reactions in biochemical systems
(human body dilute solution at 37 Β°C). Without the presence of enzymes, the reactions would take place much too slowly to sustain life.

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6
Q

Define enzymes;

A

protein molecules, catalyse a specific reaction, unchanged by
the reactions they catalyse

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7
Q

Whats the name of the model - enzyme and substrate bind?

A

Lock and Key Model

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8
Q

name of site on enzyme where substrate binds to?

A

Active site

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9
Q

Lock and key model - step by step

A

1) Substrate binds to enzyme (in active site) reversibly
2) Non-covalent interactions (enzyme-substrate complex) > reaction takes place
3) enzyme-product complex
4) product leaves to make free enzyme and free substrate

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10
Q

What INDUCED fit mean vs lock and key model

A

the active site of an enzyme will undergo a conformational change when binding a substrate, to improve the fit.

Chemical and shape compatibility of a substrate with an enzyme active site (substrate fits to active site precisely)

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11
Q

in the active sites what are two things that are present?

A

> hydrophobic region
charges +/-

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12
Q

Enzymatic reaction Profile -
Enzyme works as catalyst providing an _______ pathway for the reaction in which the rate-determining step has a lower ______ activation energy than that of the non-catalysed reaction

A

alternative

Gibbs

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13
Q

LOWER the activation energy…

A

more sufficient the reaction is = the FASTER the rate of reaction

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14
Q

Two distinct steps in enzyme catalysed reaction:

A

1) first step - reversible
2) second step - irreversible

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15
Q

Michaelis Menten model was developed to understand the kinetics of enzymic reactions.

A

E + S <> (k1/k-1)
ES > E + R (k2)

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16
Q

A number of assumptions are applied to the Michaelis Menten model:

A

The enzyme binds a single substrate (the model assumes cofactors are already bound)
There are two distinct steps. The substrate binds reversibly but product formation is irreversible
A steady state approximation applies (quantitative analysis of the kinetics of enzyme-catalysed reactions)

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17
Q

Whats the name of the state at the strart of an enzymatic reaction?

A

The steady state

18
Q

Rate of formation of ES = Rate of consumption of ES (conversion to E + P)

A

( 𝒅[𝑬𝑺])/𝒅𝒕=(Rate of formation of ES - Rate of consumption of ES)=0

19
Q

=k1 [E] [S] -k2 [ES] - k-1 [ES]

A

( 𝒅[𝑬𝑺])/𝒅𝒕=k1 [E] [S] –(k2 - k-1 )[ES]=0

20
Q

Assumption is made that: [E]0 = [ES] + [E] where [E]0=

A

total conc of enzyme

21
Q

Concentration of the substrate is usually much larger than that of the enzyme, so that [S] is effectively ______

22
Q

In the initial phase of the reaction: [E]^ and [ES]^

A

[ES] and [E] remain steady over most of the reaction time.
Only at the end of the reaction, when [S] is exhausted, does [ES] decline

23
Q

The Michaelis Menten Equation

A

𝑽 (𝒓𝒂𝒕𝒆 𝒐𝒇 π’“π’†π’‚π’„π’•π’Šπ’π’)= ( π‘½π’Žπ’‚π’™ [𝑺])/(𝑲𝑴+[𝑺])

24
Q

What kind of linear when the velocity of an enzyme catalysed reaction increases

A

a non-linear fashion

25
Q

KM=the Michaelis constant.

A

It is (k2 +k-1)/k1

26
Q

Maximal Velocity Vmax, when is Vmas reached on graph?

A

At the highest point before the gradient goes flat

When independent of the [S] = the rate of reaction remains constant at the maximum value, Vmax, and the reaction is zero order with respect to [S].

27
Q

When [S] is large, [S]&raquo_space; KM…

A

a) 𝑽 (𝒓𝒂𝒕𝒆 𝒐𝒇 π’“π’†π’‚π’„π’•π’Šπ’π’)= ( π‘½π’Žπ’‚π’™ [𝑺])/([𝑺]) = Vmax =K2 [E]0
(S cancelles each other)

b) Rate of reaction is now independent of [S]

c) All of the enzyme molecules have S attached during the reaction and [ES] = [E]0

d) The enzyme is said to be saturated. If the [S] increases, no more enzyme–substrate complexes can be formed, and the rate of the reaction is independent of [S]

28
Q

Vmax;

A

the maximum rate that a given enzyme can achieve, indicates the velocity of the reaction when the enzyme active site is saturated and indicates the maximum number of moles of S that can be processed in a unit of time (mol s-1)

29
Q

How do we know it is first order?

A

The rate of reaction increases linearly with [S]
It is first order with respect to [S].

29
Q

How do we know it is first order?

A

The rate of reaction increases linearly with [S]
It is first order with respect to [S].

30
Q

Define the turnover number;

A

number of substrate molecules converted into product by an enzyme molecule in a unit time when the enzyme is fully saturated with substrate

31
Q

What is the turnover number related to?

A

It is related to Vmax and is equivalent to the rate constant k2

32
Q

Turnover number equation

A

Turnover Number = K2 = Vmax/[E]0 (s-1)

Range from 1 to 104 s-1 in MOST enzymes

33
Q

Km, whats it used for?

A

The Michaelis constant = (k2 +k-1)/k1

gives indication of how tightly the enzyme binds its substrate

34
Q

KM= substrate concentration ([S]) at which the reaction velocity is ____ of V maximum (Vmax/2)

35
Q

Weak substrate; large or small Km?

A

large Km

a high [S] is needed to achieve Vmax/2 (and even more to reach Vmax!)

36
Q

A good substrate has a ____ Km;

A

low

Only a low [S] needed to reach Vmax.

37
Q

KM= The [S] at which the enzyme active site is ____ saturated

38
Q

Lineweaver-Burk Equation

A

The y and x axis intercepts give us the important kinetic terms Vmax and KM from easily measured properties (rate and substrate concentration)

39
Q

Why use a straight line graph than a curve?

A

easier to plot