Aromatic compounds Flashcards
Benzene formula
C6H6
C-C bonds in benzene are all equal =
1.4Å (single C-C 1.54Å, double C=C 1.33Å)
Resonance hybrid of the two Kekulé structures: the pi electrons are _________
delocalised
Aromatic compound:
be a cyclic compound containing some number of conjugated double bonds and having an unusually large resonance energy
Aromatic compounds meet the following criteria:
[4]
1] Structure must be cyclic, containing some number of conjugated pi bonds
2] Each atom in the ring must have an unhybridized p orbital. Usually sp2 or occasionally sp hybridised
3] Unhybridized p orbitals must overlap to form a continuous ring of parallel orbitals (conjugated). Structure must be planar (or nearly planar) for effective overlap to occur
4] Delocalisation of the pi electrons over the ring must lower the electronic energy
Antiaromatic compound:
meets the first three criteria, but delocalisation of the pi electrons over the ring increases the electronic energy
Aromatic structures are _____ stable than their open-chain counterparts
more
What is a Nonaromatic compound (aliphatic)?
cyclic compound that does not have a continuous, overlapping ring of p orbitals. Its electronic energy is similar to that of its open-chain counterpart
Aromatic or antiaromatic: a cyclic compound must have
a continuous ring of overlapping p orbitals, usually in a planar conformation
Benzene (4N+2) = N=1. How many pi electrons can the benzene obtain?
6 pi e-
sp3 carbon is nonaromatic because
no unhybridized p orbital and no continuous ring of p orbitals
4N the system is
nonaromatic
sp3 present
nonaromatic
When carbon have -ive charge it is sp2 instead of sp3
antiaromatic
when a carbon is +ive NOT sp3 but sp2
aromatic
4 pi e- system with N=1 obtains
4N = 4 pi e-
Derivative of benzene:
substituents named just as they were attached to an alkane