Colour by Design 2: Benzene Structure Flashcards
In general describe the structure of benzene ( 3 )
- 6 C atoms arranged in regular hexagon arrangement
- Each C atom bond to one H ( determined using empirical method ) = C6H6 ( determined by molecular method )
- All bond angles = 120° = planar molecule
Name the 2 suggested structures for benzene
- Kekule Benzene Structure
2. Delocalised Benzene Structure
Describe the structure of Kekule benzene structure
Alternating single and double bonds between the carbons
Name = cyclohex-1,3,5-triene
Describe delocalised benzene structure
- p orbitals, 1 from C atom and each containing 1 electron, overlap
- = 2 rings of delocalised electrons 1 above and 1 below the plane of the ring
( valence bond theory )
- = increased stability ( due to delocalised electrons )
( be able to illustrate this process )
Describe valence bond theory in benzene
???
- p orbitals sideways overlap to form pi bonds
- Pi bonds are delocalised
To do with sigma pi bonds
What are the 3 main pieces of evidence to suggest that Kekule Benzene structure is incorrect
- Reaction= bromine water remains orange ( doesn’t go colourless ) / chlorination of benzene requires catalyst whereas no catalyst needed for alkenes
- Thermal stability = enthalpy change of hydrogenation is less EXOthermic for benzene ( than for Kekule model )
- Bond lengths = carbon-carbon bond lengths are the same in benzene
Explain the evidence in terms of reaction with bromine water
- normally alkene + bromine = orange —> colourless ( electrophilic addition )
- benzene + bromine = remains orange ( not a normal alkene despite the C=C bonds in Kekule structure )
- therefore benzene undergo substitution rather than addition reactions
Explain evidence in terms of thermal stability
- cyclohexene = 1 double bond
—> when add hydrogen ( H2 ) = Enthalpy change = -119 kJmol-1 - if benzene had 3 double bonds ( Kekule structure ) = expect to have enthalpy of hydrogenation of -360 kJmol-1
- but experimental of enthalpy = -208 kJmol-1 = less EXOthermic than expected
- less energy released ( when breaking bonds Bendo Mex ) = benzene more stable than Kekule structure suggests ( due to delocalised ring of electrons )
Explain evidence in terms of bond lengths and geometry
- single bonds longer than double bonds = Kekule benzene structure = distorted = not a regular hexagon
However actual benzene = ….
- Benzene = all C-C bonds lengths = identical ( length = somewhere between length of single & double bond )
- benzene = perfect regular hexagon because no distortion = implying not alternating => kekule incorrect
What are the carbon-carbon bonds in benzene all the same length
Pi bonds in benzene are delocalised