cgier 35 Flashcards
all living things are – depending heavily on – equilibrium especially —-
- water based
- aqoues
- acid base equilibria
( proteins , dna , blood , acid and base groups which are found in macromolecules ( proteins ) and smaller molecules)
in arhenous definition acid and bases are :
acids are —
bases are —-
- gives h+ ions
- oh- ions
in browsed Lowry acid and bases are:
acids :
bases :
- h+ donors
-+h accepotors
blood plasma ph is —-
7.35 - 7.45
— are systems of chemical equilibria that can resist serious changes in the PH upon the addition of acids and bases
buffer
– is an example of amphoteric which means it acts as an acid if – in found and acts as base if —
- h20
- presence of base
- presence of acid
— completely dissociate in water and is 100% ionisation in aqoues solution
examples:
strong acids
- HCL04 > HI > HBR > HCL > H2SO4 > HNO3
hcl is a — and once it dissociates we’ll get the following products :
- strong acids
- HCl –> h30- + cl-
strong bases will — in water and are 100% ionised in aqueous solution such as:
- dissociate completely
- NaOH , KOH , Ba(OH) , LiOH
such as: NaOH –> Na+ OH-
( weak acids include : nh3 , ch3nh2)
stronger the acid — the conjugate base
stronger the base — the conjugate acid
in these situations of strong acids and bases we use – arrows
weaker, weaker , single headed arrows
the Ka and Kb express the relative concentration of —- species at equilibrium and their typical values are —
ionised ( charged ) and unionised
so :
ionised ( charged aka products) / unionised ( reactants )
values are less than 1 ( 10-3 to 10-10 )
-by using the Ka and Kb we predict the — of the weak acids and weak bases
- the weak acids and bases ionises — and we use – arrow
-strength
- partially
- equilibrium
1-what is Kw —
2-the pure water can slightly conduct — due to —-
3- the kw value is:
4- the kw is constant with – and increases with —
5- Kw is = to —- for a —
- the ion product of water by which we will have 2 water moliocules to produce :
h20 + h20 –> h3o+ + oh- - slightly conduct electricity bc of autodissosiation
- 1 x 10-14 at 25 c
- constant w/ given temp and increases with tempreture
- Ka x Kb for a conjugate acid-base pair
Ka x Kb will give
to find Ka:
to find kb :
Kw bc Ka x Kb = (h3O+) (OH-)
ka = kw / kb
kb= kw/ka
ph+ pOH =
14