*2A Weather - Nature of the Atmosphere Flashcards
- State the general characteristics in regard to the flow of air around high and low pressure systems in the Northern Hemisphere.
(AC 00-6A)
Low Pressure—inward, upward, and counterclockwise
High Pressure—outward, downward, and clockwise
- What is a “trough”?
AC 00-6A
A trough (also called a trough line) is an elongated area of relatively low atmospheric pressure. At the surface when air converges into a low, it cannot go outward against the pressure gradient, nor can it go downward into the ground; it must go upward. Therefore, a low or trough is an area of rising air. Rising air is conducive to cloudiness and precipitation; hence the general association of low pressure and bad weather.
- What is a “ridge”?
AC 00-6A
A ridge (also called a ridge line) is an elongated area of relatively high atmospheric pressure. Air moving out of a high or ridge depletes the quantity of air; therefore, these are areas of descending air. Descending air favors dissipation of cloudiness; hence the association of high pressure and good weather.
- What are the standard temperature and pressure values for sea level?
(AC 00-6A)
15°C (59°F) and 29.92” Hg
- What are “isobars”?
AC 00-6A
An isobar is a line on a weather chart which connects areas of equal or constant barometric pressure.
- If the isobars are relatively close together on a surface weather chart or a constant pressure chart, what information will this provide?
(AC 00-6A)
The spacing of isobars on these charts defines how steep or shallow a pressure gradient is. When isobars are spaced very close together, a steep pressure gradient exists which indicates higher wind speeds. A shallow pressure gradient (isobars not close together) usually means wind speeds will be less.
- What causes the winds aloft to flow parallel to the isobars?
(AC 00-6A)
The Coriolis force.
- Why do surface winds generally flow across the isobars at an angle?
(AC 00-6A)
Surface friction.
- At what rate does atmospheric pressure decrease with an increase in altitude?
(AC 00-6A)
1” Hg per 1,000 feet.
- What does “dew point” mean?
AC 00-6A
Dew point is the temperature to which a sample of air must be cooled to attain the state of saturation.
- When temperature and dew point are close together (within 5°), what type of weather is likely?
(AC 00-6A)
Visible moisture in the form of clouds, dew, or fog. Also, these are ideal conditions for carburetor icing.
- What factor primarily determines the type and vertical extent of clouds?
(AC 00-6A)
The stability of the atmosphere.
- How do you determine the stability of the atmosphere?
AC 00-6A
Unstable air is indicated when temperature decreases uniformly and rapidly as you climb (approaching 3°C per 1,000 feet). If temperature remains unchanged or decreases only slightly with altitude, the air tends to be stable. Instability is likely when air near the surface is warm and moist. Surface heating, cooling aloft, converging or upslope winds, or an invading mass of colder air may lead to instability and cumuliform clouds.
- List the effects of stable and unstable air on clouds, turbulence, precipitation and visibility.
(AC 00-6A)
Stable Stratiform clouds Smooth turbulence Steady precipitation Fair to poor visibility Unstable Cumuliform clouds Rough turbulence Showery precipitation Good visibility
- At what altitude above the surface would the pilot expect the bases of cumuliform clouds if the surface temperature is 82° and the dew point is 62°?
(AC 00-6A)
You can estimate the height of cumuliform cloud bases using surface temperature/dewpoint spread. Unsaturated air in a convective current cools at about 5.4°F (3.0°C) per 1,000 feet; dew point decreases at about 1°F (5/9°C). Thus, in a convective current, temperature and dew point converge at about 4.4°F (2.5°C) per 1,000 feet. You can get a quick estimate of a convective cloud base in thousands of feet by rounding the values and dividing into the spread. When using Fahrenheit, divide by 4 and multiply by 1,000. This method of estimating is reliable only with instability, clouds and during the warmer part of the day.
Temp - Dew Point
——————— x 1,000 = Base of clouds
4
82 – 62 = 20
20 ÷ 4 = 5
5 x 1,000 = 5,000 feet AGL