Worksheets 5-7-Series/Parallel Circuit Calculations

Question 1

What is the rule for calculating total resistance in a series circuit?

Answer 1

The total resistance in a series circuit is the sum of all of the resistors:

R_T=R₁+R₂+R₃

Question 2

What is the rule for current in a series circuit?

Answer 2

Total current in a series circuit is equal across all of the resistors equally.

I_T=I_R1=I_R2=I_R3

Question 3

What is the rule for voltage in a series circuit?

Answer 3

Total voltage of a series circuit is equal to the sum of the voltage drops of the individual resistors.

E_T = E_R1+E_R2+E_R3

Question 4

Referring to the diagram, what is the total resistance?

Answer 4

RT=30Ω+10Ω+15Ω

RT=55Ω

Question 5

Using the diagram, what is the total current?

Answer 5

I_T=135V/55Ω

I_T=2.45A

Question 6

What is the voltage drop across R₂?

Answer 6

E_R2=10Ω x 2.45A

E_R2=24.5V

Question 7

For this circuit, what is the total voltage applied?

Answer 7

R_T=4kΩ+6kΩ+10kΩ

R_T=20kΩ

E_T=20kΩ x 5mA

E_T=100V

Question 8

What is the voltage drop across R₃?

Answer 8

E_R3=10kΩ x 5mA

E_R3=50V

Question 9

What is the rule for voltage distribution in a parallel circuit?

Answer 9

E_T is equal in all branches of a parallel circuit.

E_T=E_R1=E_R2=E_R3

Question 10

What is the rule for current paths in a parallel circuit?

Answer 10

I_T is the sum of current in all branches.

I_T=I_R1+I_R2+I_R3

Question 11

What is the rule for total resistance in a parallel circuit?

Answer 11

Total resistance in a parallel circuit is equal to the inverse of the sum of the inverse resistance in each branch.

1/R_T=1/R₁+1/R₂+1/R₃

Question 12

Referring to the diagram, solve for total resistance.

Answer 12

1/R_T=1/10Ω+1/40Ω+1/80Ω

1/R_T=0.1+0.025+0.125

1/R_T=0.1375

R_T=7.27Ω

Question 13

Using the product over sum method, solve for the total resistance for this circuit.

Answer 13

R_T=(10Ω x 10Ω) / (10Ω + 10Ω)

R_T=100Ω/20Ω

R_T=5Ω

Question 14

Determine the total resistance for this circuit using the equal branches method.

Answer 14

R_T=45Ω/3

R_T=15Ω

Question 15

For this circuit, solve for the total source current.

Answer 15

I_T=E_T/R_T

I_T=10kΩ / 2 = 5kΩ

5kΩ/2 = 2.5kΩ

I_T=9V/2,500Ω

I_T=0.0036A = 3.6mA

Question 16

For this circuit, determine the following:

R_T=

E_T=

E_R1=

I_R1=

I_R2=

E_R3=

I_R3=

Answer 16

R_T=10kΩ

E_T=50V

E_R1=50V

E_R2=50V

E_R3=50V

E_R4=50V

I_R1=2.5mA

I_R2=0.625mA

I_R3=1.25mA

I_R4=0.625mA

Question 17

Refer to the diagram and determine the following:

R_T=

E_T=

E_R1=

E_R2=

E_R3=

I_R1=

I_R2=

I_R3=

Answer 17

R_T=10Ω

E_T=10V

E_R1=6V

E_R2=4V

E_R3=4V

I_R1=1A

I_R2=0.5A

I_R3=0.5A

Question 18

Refer to the diagram and determine the following:

R_T=

E_T=

E_R1=

ER₂=

E_R3=

E_R4=

E_R5=

E_R6=

E_R7=

I_R1=

I_R2=

I_R3=

I_R4=

I_R5=

I_R6=

I_R7=

Answer 18

R_T=30Ω

E_T=90V

E_R1=90V

E_R2=18V

E_R3=27V

E_R4=45V

E_R5=25.2V

E_R6=19.8V

E_R7=19.8V

I_R1=3A

I_R2=1.8A

I_R3=1.8A

I_R4=0.9A

I_R5=0.9A

I_R6=0.6A

I_R7=0.3A