Weak spots Flashcards
What knot creates a non-slip loop in the end of the rope?
Bowline
How far beyond the face of the chimney wall must a chimney cap project? 1/1 POINT
9.21.4.6. Chimney Caps
1 The top of a chimney shall have a waterproof cap of
reinforced concrete, masonry or metal.
2 The cap required in Sentence 1 shall slope from the
lining and be provided with a dip not less than 25 mm from
the chimney wall.
On a builders level with four thumb leveling screws, which direction would you turn the thumbscrews to move the bubble in the vial to the left?
turn the screws outward
Ladders are required to extend how far above the working platform or landings?
0.9m
Any worker in danger of falling m must wear fall protection
3.0
What is the chemical process through which cement hardens when water is added to mixed concrete?
Hydration
- What is the minimum distance a treatment unit (septic tank) may be located from the building?
1.5m
The B.M. is 106.42’, the H.I. is 111.89’ and the F.S. is 3.89’. What is the new elevation?
108.00’
An excavation for a 12” deep footing has been flooded by 6” of water for several days. What
needs to be done in order to place concrete?
Pump out the water, excavate mud to undisturbed soil
To prevent excessive checking, scaffold planks should:
Have their ends banded with steel
When applying laminate to a counter top
Apply the side edges first
Which of the following knots is best for safely shortening a rope?
sheepshank
The main floor of a house has 13 interior doors and 2 exterior doors. Allowing 7' for side casings and 3' for head casings, how many linear feet of material would you need to trim these doors? 0/1 POINT A 221' B 255' C 476' D 510'
476’
How many cubic yards of concrete is needed to build a silo with the following specifications? Inner radius= 72'7" Outer radius= 74'3" Height = 125'
3,559.348765 yd³
A building is 35 yards tall, how many feet tall is it?
105’
A footing form will require 6.5 cubic yards of concrete. How many cubic feet is this?
175.5 ft3
An excavation for a 12” deep footing has been flooded by 6” of water for several days. What needs to be done in order to place concrete?
Pump out the water, excavate mud to undisturbed soil
Cove moulding can be shaped on a table saw by feeding the stock:
At approximately 45° to the blade
What is the minimum clearance required above a fireplace for a projecting 50 mm X 250 mm X 1,500 mm oak mantel shelf?
9.22.9.1
300mm
What are the three parts of a knot?
Standing part, bright, and running end.
At what height does a system scaffold need to have an engineered drawing?
15 m
A scaffold shall be designed by a professional engineer and shall be erected in accordance with the design if the scaffold exceeds,
(a) fifteen meters in height above its base support; or
(b) ten meters in height above its base support if the scaffold is
constructed of a tube and clamp system. O.Reg. 213/91, s. 130 1
What is the maximum size of structure that can be built under part 9 of the building code?
3 storey and 600 m² per floor.
A building is 35 yards tall, how many feet tall is it?
35 yd. X 3 ft./yd = 105’
- Referring to “Wall Section A”, what is the distance from finished grade to the top of the concrete slab?
2”
9.15.4.6.(1)
not less than 150mm above finished ground level
Referring to “Wall Section A”, how many nails (and at what length) would you need to use at the connection between the 2X6’s and 2X8’s?
If we look at the drawing and check the sizes of framing members at each
location, we can see that the only place we have 2 X 6’s and 2 X 8’s together is
at the intersection between our rafters and our ceiling joists. Because we are
securing the rafters to joists, the edge can be considered as being supported.
Using the information we have gathered to navigate the nailing chat for framing
Table9.23.3.4, we can located the item that best identifies the location in
question:
Item 21 Rafter to joist(with idge supported):
Length of nail = 76mm
Minimum number of nails= 3
Referring to “Wall Section A”, what is the height from subfloor to
finished ceiling in the second storey if you are using 5/8” drywall?
8’ - 0 5/8”
- Referring to “Wall Section A”, what is the actual distance of the
cantilevered floor frame?
the portion of the floor frame that projects past the wall below is 2’0”
which is equal to 24”.
Referring to “Wall Section A”, what type of cornice is used?
Types of cornices…
BOX Rafters or roof framing members overhang the wall and these
structure members are covered (boxed) in by finish materials. Soffit may follow the sloping underside of the rafters or be applied level
by adding nailing blocks (sometimes referred to as lookouts) between the
rafter tail ends and the wall. Rafter ends must be aligned accurately both
horizontally and vertically.
Referring to “Wall Section A”, to what elevation would you excavate for your basement if the finished grade elevation is 729’ 3 5/8”?
height of our wall 7’4”), deduct the distance the wall projects above
finished grade 2”), and add the additional depth required for the
layer of gravel that is laid below the slab:
Depth of excavation = 7’4” - 2” + 4” = 7’6” = 7.5’
Next, you can either keep your measurements in feet and inches and
subtract them from your total:
729’3 5/8” - 7’6” = 728’15 5/8” - 7’6” = 721’9 5/8”
Or, you can also convert to decimal feet, subtract your distance and
convert back to feet, inches and fractions of an inch:
58 = 0.625” + 3” = 3.625” ÷ 12 inches/foot
= 0.3020833’ + 729’ = 729.30208333’
729.30208333’ - 7.5’ = 721.80208333’
721.80208333 - 721 = 0.80208333 X 12 = 9.625 - 9
= 0.625” X 16 = = 721’9 5/8”
10 16
=
5 8
Referring to “Wall Section A”, what type of material could be used for building paper according to the building code?
Key words: Eaves, shingle and shakes
9.26.5. Eave Protection for Shingles and Shakes
9.26.5.2. Materials
1 Eave protection shall be laid beneath the stater stip and shall consist of,
(a) No. 15 asphalt-saturated felt laid in two plies lapped 480 mm and
cemented together with lap cement.
. Referring to “Wall Section A”, the 10” thick drops are included for:
Looking at the section, we can see that the cantilevered section of the floor gets its structural support from being incorporated into the second floor framing. The support is provided by the full floor system and diagonal bracing is not required. We can also rule out the possibility of it being a tie in for the bricks, as it sits above the bricks and is tied into the wood sheathing that overlaps the bricks slightly. If you look at the brick section you can see that ties run from the sheathing behind the bricks through the veneer every 5th course.
Referring to “Wall Section A”, what additional measures must be taken to provide adequate foundation drainage to the structure?
drainage tile needs to be surrounded by crushed stone.
Using keywords: Drainage Tile and Pipe,
9.14.3. Drainage Tile and Pipe
9.14.3.3. Installation
4 The top and sides of drain pipe or tile shall be covered with not
less than 150 mm of crushed stone or other
coarse clean granular material containing not more than
10% of material that will pass a 4 mm sieve.
Referring to “Wall Section A”, what is the R-value of the attic insulation?
Answer: R22
Referring to “Wall Section A”, what is the metric equivalent of your
ceiling joist dimension?
Joist thickness= 1½” X 25.4 mm/inch = 1.5” X 25.4 mm/inch = 38.1mm ≈ 38mm
Joist Depth= 7¼” X 25.4 mm/inch = 7.25” X 25.4 mm/inch = 184.15mm ≈ 184mm
Referring to “Plan B”, what size door is used for the linen closets?
1’6” X 6’8”
Referring to “Plan B”, at least one window in PATRICIA’S BR must provide an unobstructed opening of not less than:
9.9.10. Egress from Bedrooms
9.9.10.1. Egress Windows or Doors for Bedrooms
1 Except where a door on the same floor level as the bedroom provides direct access to the exterior, evey floor level containing a bedroom in a suite shall be provided with at least one outside window that, (a) is openable from the inside without the use of tools,
(b) provides an individual, unobstructed open potion having a minimum area of 0.35 m² with no dimension less than 380 mm, and…
Referring to “Plan B”, the length of the STUDY is:
14’9”
Referring to “Plan B”, you need to reduce the hallway leading to RICKY’S BR. What is the minimum unobstructed width you can reduce the
hallway to?
9.5.10. Hallways
9.5.10.1. Hallway Width
1 The unobstructed width of a hallway within a
dwelling unit shall be not less than 860 mm, except that the
hallway width is permitted to be 710 mm, where,
(a) there are only bedrooms and bathrooms at the end of
the hallway furthest from the living area, and
(b) a second exit is provided,
Referring to “Plan B”, how much clearance is required between the STUDY wall wood framing and the masonry chimney?
100 mm
9.22.9.3
Referring to “Plan C”, how many cubic feet of concrete would you need for your column footings?
footings have the following dimensions:
Width= 2’
Length= 2’
Depth= 1’
First, determine the volume of a single footing:
Volume = Width X Length X Depth = 2’ X 2’ X 1’ = 4 ft³
Next, multiply the volume of a single footing by the total number of footings:
4 ft³/footing X 5 footings = 20 ft³
Referring to “Plan C”, if you used unreinforced 10” concrete block in place of the poured concrete for your foundation wall, what would the
maximum allowable height of finished ground above basement floor be
(foundation wall is laterally supported at the top)?
9.15.4.2. Foundation Wall Thickness and Required Lateral Support
1 Except as required in Sentence 2, the thickness of foundation walls
made of unreinforced concrete block or solid concrete and subject to lateral
earth pressure shall conform to Table 9.15.4.2.A. for walls not exceeding 3.0
m
in unsupported height.
Referring to “Plan C”, what room is the floor drain in?
shop
Referring to “Plan C”, what is the dimension of distance “Z”
48’9”
Referring to “Plan C”, what is the supported joist length for the W8X20 beam in the GAME ROOM?
12’ 6 1/2”
Referring to “Plan C”, how many pilasters are there?
5
What is the minimum clearance required above a fireplace for a projecting 50 mm X 250 mm X 1,500 mm oak mantel shelf?
Section 9.22. Fireplaces
9.22.9. Clearance of Combustible Material
9.22.9.1. Clearance to the Fireplace Opening
1 Combustible material shall not be placed on or near the face of a fireplace within 150 mm of the fireplace opening, except that where the combustible material projects more than 38 mm out from the face of the fireplace above
the opening, such material shall be at least 300 mm above the top of the opening
- What is the minimum safe distance you must maintain from a 125,000 volt powerline while working?
3m
At what height does a system scaffold need to have an engineered drawing?
A scaffold shall be designed by a professional engineer and shall be erected in accordance with the design if the scaffold exceeds,
(a) fifteen meters in height above its base support; or
(b) ten meters in height above its base support if the scaffold is
constructed of a tube and clamp system. O.Reg. 213/91, s. 130 1
Note: (a) applies to system scaffolds and (b) applies to tube and clamp scaffolds.
How many square yards of drywall would you need to cover a wall measuring 22’0’’ X 9’0”? 0/1 POINT
22 yd²
How many cubic inches of wood chips are there in a tank containing 15 cubic feet of them?
25,920 in³
What is the purpose of dimple board membrane?
To provide a drainage layer for foundation walls below grade
What is the main purpose of installing coarse gravel under concrete slabs?
Answer: To mitigate the effects of capillary action
What is the maximum size of structure that can be built under part 9 of the building code?
3 storey and 600 m² per floor
If a drawing is scaled at 1/4”1’0”, how long would a line need to be to represent 18’0”?
Take your dimension in feet and multiply it by the smaller increment that represents a foot (in this case 1/4”):
18’ X 0.25inches/foot= 4.5” = 4 1/2”
When 1”X8” bevel siding is applied to a building with 63/4” exposed to the weather, what height would be covered by 15 courses?
To calculate your distance of coverage, multiply your exposure per course by the number of courses, then convert back to inches and fractions of an inch:
6.75inches/course X 15 courses = 101.25” = 101 1/4”
The material needed for a deck is estimated to be 81.9 BF. What would the total cost of material be at a piece of 1.65$/BF
To calculate your material cost, multiply your quantity in board feet by your price per board foot: material cost = 81.9 BF X 1.65$/BF = $135.135 ≈ $135.14
If a stack of 3/8” plywood is 201/4” tall, how many sheets high would it be?
To calculate the number of sheets, take your total height in decimal inches and divide it by the thickness of a single sheet in decimal inches:
20.25” ÷ 0.375inches/sheet = 54 sheets
In setting from work for a sidewalk, a carpenter is asked to raise the from 3/4” above an elevation of 141.35’. What is the new elevation?
o determine the new elevation, convert the amount you are raising the form into decimal feet, and then add it to the original elevation:
0.75” ÷ 12inches/foot= 0.0625’
New elevation = 141.35’ + 0.0625’ = 141.4125’
- Given the information on the right, what is the height of the
instrument? - Given the information on the right, what is the elevation at point
A? - Given the information on the right, what is the elevation at point
B? - Given the information on the right, what is the difference
between point A and point B?
- H.O.I.= benchmark elevation + measurement above benchmark
= 102.50’ + 5.05’ = 107.55’ - Elevation = Height of instrument - foresight reading
= 107.55’ - 7.35’ = 100.20’ - Elevation = Height of instrument - foresight reading = 107.55’ - 4.93 = 102.62’
- To find the difference, subtract the lower elevation from the higher elevation:
- 35’ A - 4.93’ B = 2.42’
- Both side of the roof shown on the right are covered with asphalt
shingles. What is the area to be covered?
width = 15’9” = 15.75’
length = 42’6” = 42.5’
1,338.75 ft²
- What is the capacity of the silo on the night (from top of slab to top of walls)?
- How many cubic yards of concrete would be required for the walls of
the silo at night?
- 10,730.13 ft³
36. ≈ 45.74 yd³
A builders’ level reads a back sight of 3.011’ over a known elevation point of 785.232’. What is the height of the instrument?
Height of instrument = known elevation + back sight = 785.232’ + 3.011’ = 788.243’
What is the area of the triangle?
base = 950mm
height = 275mm
Area of a triangle = (base x height )/ 2 ) = 130, 625 mm
Given the following roof specifications, what is the slope of the roof?
South end elevation= 275.305’
North end elevation= 269.488’
End to end distance= 185
slope of roof = south end elevation - north end elevation X 100 End to end distance
′
= (375.305’ - 269.488’)/185’ x 100
= 3.14%
What is the area of the triangle?
Base = 219.9375’
Height = 124.739583’
Area of triangle = base x height/ 2
= 13, 717.456 ft²
What is the length of the sides of an octagon whose overall width is
12’ 8
The easiest way to calculate the length of the sides of an octagon is to draw a square with four sides measuring the desired width of your structure,
calculating the hypotenuse and subtract the dimension of one side from the
hypotenuse dimension. The remainder will represent the length of each side:
√(12.66667′) + (12.66667 ) = = 17.9133765
Hypotenuse =
2 ′ √320.88905778ft²′
Length of sides = hypotenuse - desired width
= 17.9133765’ - 12.66667’
= 5.2467065’ ≈ 5’ 215⁄16”
You are using a construction grout that cures at a rate of 0.0579inches/hour. How long will it take for a section that is 95/8” deep to cure?
First, convert the thickness into decimal inches:
5 ÷ 8 = 0.625” + 9” = 9.625”
Next, divide the thickness by the rate of cuing to get your answer in hours:
9.625” ÷ 0.0579inches/hour= 166.2348877 hours ≈ 166.235 hours
Finally, divide your hours by 24 to convert into days:
166.235hours ÷ 24hours/day = 6.9264583days ≈ 7days = 1 week
An ellipse has a major axis of 175mm and a minor axis of 68mm. To replicate the same ellipse at a larger scale with a minor axis of 300m, what size will the major axis be?
Convert all measurements into meters: Original ellipse: major axis = 175 mm ÷ 1,000mm/M= 0.175 m minor axis = 68mm ÷ 1,000mm/M= 0.068 m New large scale ellipse: major axis = x minor axis = 300 m Next, solve for x using ratio and proportion:
x
0.175m
=
300m 0.068m
0.175m × 300m
∴
x = = 772.0588m≈772m 0.068m
How much concrete can be placed into a cylindrical form with a diameter of 28” and a height of 35’7 1/2”?
First, convert your dimensions into decimal feet:
diameter = 28” ÷ 12inches/foot = 2.33334 ‘
height = 7.5” ÷ 12inches/foot) + 35’ = 0.625’ + 35’ = 35.625’
Next, use your diameter to determine the circular area of the top of your fom:
use π = 3.1416
radius (r) = diameter ÷ 2 = 2.33334’ ÷ 2 = 1.16667’
area of circle = π² = 3.14161.16667’)² = 4.2760911 ft²
A shed roof measuring 16’ X 28’ is covered with asphalt shingles. If the shingles weigh 235 lbs. per square, and the nails weigh 4.5 lbs. per square, what is the total weight of the shingle and nails you installed?
First, calculate the total area of your roof in square feet and divide your total by 100 1 square of shingles = 100 ft²):
roof area = 16’ X 28’ = 448 ft² ÷ 100ft²/square= 4.48 squares
Next, multiply the weight per square of your shingles by the number of squares, multiply the weight per square of your nails by the number of squares, and add your two weights to get your total material weight:
weight of shingles = 235lbs/square X 4.48 squares = 1,052.8 lbs.
weight of nails = 4.5lbs/square X 4.48 squares = 20.16 lbs.
total material weight = 1,052.8 lbs. + 20.16 lbs. = 1,072.96 lbs.
