Unit 1 - 4 - Hard Flashcards
Cyclin D stimulates the phosphorylation of DNA polymerase, which activates the DNA polymerase. Describe how an enzyme can be phosphorylated.
- Attachment/association of (inorganic) phosphate (to the enzyme)
- (Released from) hydrolysis of ATP
It can be 6-12 months before HPV antibodies can be detected in the blood of individual with a HPV infection. Use Figure 1 to suggest why this is.
It takes 6-12 months for antibodies to be detected in a HPV infection because:
Few virus proteins are expressed in the lower layers of the epidermis, so infected cells do not become antigen-presenting cells: [1 mark]
Viral proteins/antigen-presenting cells produced at the skin surface are quickly lost/shed from the body, so are not detected by the cells of the immune system; [1 mark]
Without antigen-presenting cells, T cells / B cells are not activated; [1 mark]
[Total: 3 marks]
Figure 2shows the SGLT1 polypeptide with NH2at one end and COOH at the other end.Describe how amino acids join to form a polypeptide so there is always NH2at one end and COOH at the other end.
- One amine/NH2group joins to a carboxyl/COOH group to form a peptidebond;
Accept on diagram, for example (at least) two amino acids joining by a correctly drawn peptide bond (MP1) with NH2at one end and COOH at the other (MP2).Ignore incorrect names of NH2and COOH groups.
- (So in chain) there is a free amine/NH2group at one end anda free carboxyl/COOH group at the otherOREach amino acid is orientated in the same direction in the chain;
Oedema is a condition characterised by an abdomen and limbs that are swollen with fluid. It is prevalent in poorly developed areas in the African continent due to the low protein diet of the people living there. Explain how a low protein diet could result in oedema.
A low protein diet could result in oedema because:
- Low protein levels result in fewer plasma proteins in the blood; [1 mark]
This means that the water potential of the plasma is increased / too high / not low enough (at venule end of capillary); [1 mark]
Water is not reabsorbed / less water is reabsorbed by osmosis into capillaries/blood;
[1 mark]
- Tissue fluid collects/builds up in the tissues in the abdomen and limbs; [1 mark]
Explain the difference in the structure of the starch molecule and the cellulose molecule shown in the diagram above.
Starch formed from α-glucose but cellulose formed from β-glucose;
- Position of hydrogen and hydroxyl groups on carbon atom 1 inverted;
State two functions of membranes in living cells.
Any two of the following:
Separate the internal cell environment from the external environment; [1 mark]
- Separate the internal cellular compartments/organelles; [1 mark]
- Enable cellular conditions to be different between one enclosed space and another;
[1 mark]
Regulate the movement/exchange of substances; [1 mark]
An interface for communication / displaying antigens / displaying receptors; [1 mark]
Describe the roles of iron ions, sodium ions, and phosphate ions in cells.
Iron ions
- Haemoglobin binds/associates with oxygen
OR
Haemoglobin transports/loads oxygen;
Ignore reference to 2+ or 3+ in Fe2+ or Fe3+
Sodium ions
- Co-transport of glucose/amino acids (into cells);
- (Because) sodium moved out by active transport/Na – K pump;
- Creates a sodium concentration/diffusion gradient;
- Affects osmosis/water potential;
Phosphate ions
- Affects osmosis/water potential;
Accept 5. OR 6. – not both
- Joins nucleotides/in phosphodiester bond/in backbone of DNA/RNA/in nucleotides;
- Used in/to produce ATP;
Reject ‘energy produced’
- Phosphorylates other compounds (usually) making them more reactive;
- Hydrophilic/water soluble part of phospholipid bilayer/membrane;
Draw an antibody
Particulate matter is solid particles and liquid particles suspended in the air. Polluted air contains more particulate matter than clean air. A high concentration of particulate matter results in the death of some alveolar epithelium cells. If alveolar epithelium cells die inside the human body they are replaced by non-specialised, thickened tissue. Explain why the death of alveolar epithelium cells reduces gas exchange in human lungs.
- Reduced surface area;
- Increased distance for diffusion; Accept description of efficient gas exchange in the healthy alveolar epithelium as long as a reference is made to the damaged tissue changing this.
- Reduced rate of gas exchange;
Figure 1 below shows a cell surface membrane and some molecules of a small, nonpolar substance known as substance X.
Substance X will…
Move from the outside of the cell to the inside; [1 mark]
Directly through the cell (surface) membrane / in between the phospholipids / by simple diffusion; [1 mark]
Because…
There is a higher concentration of substance X outside the cell than inside / diffusion takes place down a concentration gradient; [1 mark]
The molecules are small and nonpolar so can move between the (tails of the) phospholipids; [1 mark]
[Total: 4 marks]
Hydrostatic pressure = 4.3 kPa Hydrostatic pressure = 1.6 kPa
Tissue fluid
Hydrostatic pressure = 1.1 kPa
(a) Use the information in the figure above to explain how tissue fluid is formed
1.
(a) 1. (Overall) outward pressure of 3.2 kPa;
2. Forces small molecules out of capillary.
Scientists have found that transcription of the LAT gene produces a microRNA.
This microRNA binds to some of the nerve cell’s own mRNA molecules. These mRNA molecules are involved in programmed cell death of nerve cells. The scientists concluded that production of this microRNA allows HSV to remain in the body for years
(d) The scientists concluded that production of this microRNA allows HSV to remain in the body for years (lines 10–12).
Explain how this microRNA allows HSV to remain in the body for years.
(d) MicroRNA binds to cell’s mRNA (no mark)
1. (Binds) by specific base pairing;
2. (So) prevents mRNA being read by ribosomes; 3. (So) prevents translation / production of proteins;
4. (Proteins) that cause cell death.
c) Genetics and nutrition are two factors that influence blood pressure in humans. Explain how very high blood pressure may affect an individual’s circulatory and lymphatic system.
High blood pressure may result in the following effects on an individual’s circulatory system:
Increased blood pressure could damage blood vessels OR valves; [1 mark]
Increased chance of heart attack OR stroke; [1 mark]
Increased outward pressure of blood at the arterial end of capillaries; [1 mark]
Higher volume of tissue fluid forms / not all tissue fluid is reabsorbed/drains; [1 mark]
This leads to swollen limbs (due to accumulation of tissue fluid); [1 mark]
Mitochondrial disease (MD) often causes muscle weakness (lines 1–3). Use your knowledge of respiration and muscle contraction to suggest explanations for this effect of MD.
a) 1. Reduction in ATP production by aerobic respiration;
2. Less force generated because fewer actin and myosin interactions in muscle;
3. Fatigue caused by lactate from anaerobic respiration.
Describe the role of spindle fibres, mitosis
- C-prophase and
D= metaphase and
E = anaphase,
- (In) prophase, chromosomes condense
- (In) prophase OR metaphase, centromeres attach to spindle fibres,
- (In) metaphase, chromosomes/pairs of chromatids at equator/centre of spindle/cell
5 (In) anaphase, centromeres divide,
6 (In) anaphase, chromatids (from each par) pulled to (opposite) polesiends (of cell 7) prophase/metaphase anaphase, spindie
fibres shorten
(b) Give two assumptions made when using the mark-release-recapture method.
- No emigration / immigration;
- No losses to predation;
- Marking does not affect survival;
- Birth rate and death rate equal;
- (In this case) all belong to one population.
Describe the role of micelles in the absorption of fats into the cells lining the ileum
- Micelles include bile salts and fatty acids; Ignore other correct components of micelles.
- Make the fatty acids (more) soluble in water; For ‘fatty acids’ accept fats / lipids.
- Bring/release/carry fatty acids to cell/lining (of the ileum); For ‘fatty acids’ accept fats/lipids.
- Maintain high(er) concentration of fatty acids to cell/lining (of the ileum);
- fatty acids (absorbed) by diffusion;
Give oneadvantage of viewing a biological specimen using a transmission electron microscope compared with using a scanning electron microscope.
Higher resolution OR View internal structures;
Speciation is far less frequent in the reformed Amazonian forest. Suggest one reason for this.
Similar / same environmental / abiotic / biotic factors / similar / same selection pressures / no isolation / gene flow can occur (within a species);
What two measurements are needed to calculate an index of diversity?
- Number of (individuals of) each species;
Accept: ‘population’ for ‘number’ - Total number of individuals / number of species
The manufacturer concluded that enzyme B would be the best enzyme to use. Use the results from Figure 2 to evaluate this conclusion.
Any three of the following:
• Enzyme B is more effective across a range of temperatures / at lower and higher
temperatures: [1 mark]
• Enzyme B denatures at 80°C and enzyme A denatures at 60°C; [1 mark]
⚫ However, enzyme A has a higher maximum rate of reaction: [1 mark]
• Only 2 enzymes were investigated; [1 mark]
The blood plasma in Figure 1 has a more negative water potential at the venule end of the capillary compared to the arteriole end of the capillary. Explain why.
Any three of the following:
Water has diffused out via osmosis OR left the capillary; [1 mark]
Proteins in the blood are too large to leave/pass through wall of the capillary; [1 mark]
This means there is a higher/ increased concentration of blood proteins at venule end;
[1 mark]
• Higher concentration of blood proteins results in lower water potential; [1 mark]
Describe the structure of DNA
- Polymer of nucleotides;
- Each nucleotide formed from deoxyribose, a phosphate (group) and an organic/nitrogenous base;
- Phosphodiester bonds (between nucleotides);
- Double helix/2 strands held by hydrogen bonds;
- (Hydrogen bonds/paining) between adenine, thymine and cytosine, guanine
(d) Calculate the number of insects on this island 1 day after release of the marked insects.
Show your working.
(d) 10 130. Tolerance of ±1