S2.2 The covalent model HL Flashcards

1
Q

What is the first step in deducing the resonance structure of molecules and ions?

A

Draw all valid Lewis structures, considering the distribution of electrons around atoms and looking for multiple ways to place double bonds if applicable.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What does the resonance structure of a molecule or ion represent?

A

It is a hybrid of all valid Lewis structures, depicting electron delocalization over the molecule or ion, which cannot be represented by a single Lewis structure alone.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What role does electron delocalization play in the formation of resonance hybrid structures?

A

It spreads electrons across multiple atoms or bonds, contributing to the stability of the resonance hybrid by lowering the molecule’s potential energy.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Is the resonance hybrid a real transition between structures?

A

No, it is an intermediate representation with bond lengths and strengths that are averages of the possible structures, not a real transition.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

What physical evidence challenges the notion of alternating single and double bonds in benzene?

A

All carbon-carbon bond lengths in benzene are identical at 139 pm, indicating a delocalized electron system rather than distinct single and double bonds.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

How does benzene’s chemical behavior differ from compounds with double bonds?

A

Benzene exhibits unusual stability and a reluctance to undergo addition reactions, favoring substitution reactions instead, which suggests a resonance hybrid structure.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

What confirms benzene’s structure as having a ring of delocalized electrons?

A

X-ray crystallography confirms the resonance hybrid structure of benzene, showing a ring of delocalized electrons instead of alternating single and double bonds.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

How to represent species with five electron domains around a central atom using Lewis formulas?

A

Calculate total valence electrons, identify the central atom, draw basic structure with single bonds, add electrons to fulfill the octet rule (forming double/triple bonds if necessary), and add extra electrons to the central atom if it’s from period 3 or below.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How to represent species with six electron domains around a central atom using Lewis formulas?

A

Same process as for five electron domains: Calculate valence electrons, draw structure with single bonds, adjust with double/triple bonds to meet the octet rule, and place additional electrons on a period 3 (or below) central atom.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Electron domain geometry for species with five electron domains using VSEPR.

A

Possible geometries include trigonal bipyramidal, see-saw, T-shaped, or linear, depending on bonding vs. non-bonding electron pairs.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Electron domain geometry for species with six electron domains using VSEPR.

A

Possible geometries are octahedral, square pyramidal, or square planar, determined by the number of non-bonding electron pairs.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Factors influencing molecular geometry in VSEPR model.

A

Geometry is influenced by the repulsion between electron pairs, with specific bond angles characteristic for each geometry type.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Formal charge

A

The theoretical charge of an entire molecule based on the electron distribution of the atoms within the molecule.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

What is the first step in determining the preferred Lewis formula for a species with alternative Lewis formulas?

A

Calculate the formal charge by subtracting the number of non-bonding and bonded pairs of electrons from the original valence pairs of electrons for an atom before bonding.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

What does comparing formal charges among different Lewis structures help to identify?

A

The structure with formal charges closest to zero for as many atoms as possible, indicating minimal charge transfer during bonding and suggesting a more stable structure.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Why are Lewis structures with formal charges closest to zero generally preferred?

A

They indicate a structure where the distribution of valence electrons before and after bonding remains as unchanged as possible, suggesting a more stable configuration.

17
Q

What are sigma bonds?

A

Sigma bonds are chemical bonds formed through the direct overlap of atomic orbitals, involving electron density located precisely between the nuclei of two atoms.

18
Q

How are sigma bonds formed?

A

They result from the axial (head-on) overlap of various types of orbitals, including s-s, s-p, or p-p orbitals, facilitating a strong, stable bond between atoms.

19
Q

How are pi bonds formed?

A

Pi bonds are formed by the side-to-side (lateral) overlap of p-orbitals, with electron density concentrated above and below the plane of the nuclei.

20
Q

How do pi bonds differ from sigma bonds in their occurrence in molecules?

A

Unlike sigma bonds, pi bonds do not occur in single bonds but are present in double or triple bonds alongside a sigma bond.

21
Q

How can you deduce the presence of sigma and pi bonds in molecules or ions?

A

Single bonds contain only sigma bonds, double bonds contain one sigma and one pi bond, and triple bonds contain one sigma and two pi bonds.

22
Q

How do sigma and pi bonds affect bond rotation?

A

Sigma bonds allow for bond rotation due to their symmetrical electron density along the bond axis, whereas pi bonds restrict rotation due to their electron density distribution.

23
Q

Hybridisation

A

The process by which atomic orbitals within an atom mix to produce hybrid orbitals of intermediate energy.

24
Q

sp hybridisation

A

A form of hybridisation that involves 1 s-orbital and 1 p-orbital.

25
Q

sp2 hybridisation

A

A form of hybridisation that involves 1 s-orbital and 2 p-orbitals.

26
Q

sp3 hybridisation

A

A form of hybridisation that involves 1 s-orbital and 3 p-orbitals.

27
Q

Excitation

A

The process of changing an electron from a ground state to an excited state by energy absorption.