Reacting mass calculations Flashcards
another name for a balanced equation
stoichiometric equation
to do with the ratio of the amounts of reactants and products
reactant in excess
if there is enough:
- to react with all the other reactant(s)
- some of it is left over when the reaction ends
limiting reactant
other reactant in a reaction with a reactant in excess
not enough to fully react with the other reactant
example of an excess/limiting reactant
magnesium + hydrochloric acid:
after reaction:
some magnesium ribbon left
magnesium is in excess
hydrochloric acid is limiting
no magnesium left
magnesium is limiting
hydrochloric acid is in excess
limiting reactant and mass of product
how they influence each other
-mass of product formed is controlled by the mass of the reactant not in excess (limiting)
length of reaction and limiting reactant
how they influence each other
the reaction continues until all the particles of the limiting reactant have been used up
What is the mass of the product directly proportional to?
the mass of the limiting reactant
An oxide of copper is heated with excess hydrogen, H2.
In the reaction, 1.27g of copper and 0.18g of water, H2O, form.
Use this information to determine the stoichiometry of the reaction.
(Ar: H = 1, O = 16, Cu = 63.5)
amount of Cu = 1.27/63.5 = 0.02 (in moles/mol - unit for amount of substance, this value is 1 mol)
Mr of H2O = 1+1+16 = 18
amount of H2O = 0.18/18 = 0.01
ratio of Cu:H2O = 0.02:0.01 = 2:1
right hand side must be: -> 2Cu + H2O
so left hand side: Cu2O + H2
equation: Cu2O + H2 -> 2Cu + H2O
Explain why, in a chemical reaction, the mass of the reactant not in excess determines the mass of product formed.
reactant not in excess is the limiting reactant
when all its particles have been used up, the reaction stops/no product can be formed
Powdered carbon is heated with excess steam, producing 3.3g of carbon dioxide and 0.30g of hydrogen.
Determine the stoichiometry of the reaction.
(Mr: CO2 = 44, H2 = 2)
amount of CO2: 3.3/44 = 0.075 (mol)
amount of H2 = 0.30/2 = 0.015 (mol)
ratio of CO2:H2 = 0.075:0.15 = 7.5:15 = 1:2
right side: -> CO2 + 2H2
equation: C + 2H2O -> CO2 + 2H2