Halogen displacement reactions Flashcards

1
Q

What can a more reactive halogen do to a less reactive halogen?

A

displace it from its compounds

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2
Q

investigating displacement practical

A
  • adding a halogen solution to a metal halide solution
  • see if the mixture darkens, indicating a reaction

-chlorine in ‘chlorine water’ displaces bromine from sodium bromide solution

CL2 + 2NaBr -> 2NaCl + Br2

ionic equation (Na+ ions are spectator ions):

Cl2(aq) + 2Br-(aq) -> 2Cl-(aq) + Br2(aq)

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3
Q

redox reaction

A

a reaction in which both oxidation and reduction happens

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4
Q

define oxidation and reduction

A

Oxidation
Is
Loss of electrons

Reduction
Is
Gain of electrons

(OIL RIG)

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5
Q

What type of reaction are halogen displacements

A

redox reactions

e.g.: chlorine displaces bromine from bromide ions in solution

1) chlorine atoms gain electrons and are reduced to chloride ions
2) bromide ions lose electrons and are oxidised to bromine

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6
Q

Explain a redox reaction using chlorine and sodium bromide as an example

A

-chlorine is added to sodium bromide
(Cl2 + NaBr)
-both substances have a neutral charge

-chlorine displaces bromine to make sodium chloride
(Cl2 + NaBr -> NaCl + Br2)
-chlorine and bromine swap places

balanced:
Cl2 + 2NaBr -> 2NaCl + Br2

ionic equation:
-as Na is removed from the equation, the other elements in the compound gain a charge
-the charge is negative because group 7 elements form 1- ions
Cl2 + 2Br- -> 2Cl- + Br2

(the charges are always shown in the upper right of the symbol)

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7
Q

How do you write half equations, using chlorine and sodium bromide as an example?

A

the loss or gain of electrons is always shown by + ne-

the e- represents the charge of the lost/gained electrons
the n is how many are gained or lost

the electrons are never - from the equation

in reduction the electrons are shown on the left side to indicate a gain of electrons:
Cl2 + 2e- -> 2Cl-

in oxidation the electrons are shown on the right to indicate a loss of electrons/the electrons separating from the substance:
2Br- -> Br2 + 2e-

(the substances are balanced as the uncharged atoms exist in pairs)

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8
Q

A student adds a few drops of halogen solutions to small volumes of potassium halide solutions on a potting tile.

The three halides and halogens used are chlorine, bromine and iodine

State which potassium halides are displaced by:

a) chlorine
b) bromide
c) iodide

A

a) bromide and iodide
b) iodide
c) none of them

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9
Q

Aqueous bromine solution reacts with aqueous potassium iodide solution

a) write the balanced equation and the ionic equation
b) explain, with the help of half equations, why this reaction is a redox reaction

A

a) Br2(aq) + 2KI(aq) -> 2KBr(aq) + I2(g)
Br2 + 2I -> 2Br + I2

b) bromide atoms (in Br2) gain electrons and are reduced to bromide ions

Br2 + 2e- -> 2Br-

Iodide ions lose electrons and are oxidised to iodine

2I- -> I2 + 2e-

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10
Q

State and explain whether astatine will react with potassium iodide solution

A

astatine will not react with potassium iodide solution because

  • reactivity decreases down group 7
  • astatine is less reactive than iodine
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11
Q

ionic equation

A

an equation that includes the charges of the ions

spectator ions can be left out

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12
Q

spectator ions

A

ions that are unchanged (in charge) during a reaction

e.g. Na in the reaction of chlorine with sodium bromide

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13
Q

In a redox reaction, what happens to:

a) atoms that gain electrons
b) ions that lose electrons

A

a) they are reduced to chloride ions
(‘reduced’ because reduction is gain of electrons)

b) they are oxidised to atoms

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14
Q

Why are atoms that gain electrons described as ‘reduced’ to ions?

A

reduction is the gain of electrons

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