MMT: Carbohydrates I and II Flashcards
understand the group I love most in the world: carbs <3
define monosaccharides and name the major examples of monosaccharides
one sugar; glucose, galactose, fructose, mannose
define disaccharide and name the major examples of disaccharides
two sugars linked with an o-glycosidic linkage; sucrose, lactose, maltose, trehalose
define polysaccharide and name the major examples of polysaccharides
10+ sugars linked with an o-glycosidic linkage; glycogen starch, cellulose
what are two examples of heteropolysaccharides?
chitin and hyaluronic acid
name the major metabolic fates of glucose
becoming glycolipids and glycoproteins, entering the pentose phosphate pathway, glycolysis, becoming glycogen, and becoming amino acids
define aldose and ketose
an aldose in a carbohydrate with an aldehyde group at C-1, a ketose is a carbohydrate with a ketone group at C-2
name the secondary metabolic fates of glucose (via acetyl CoA)
entering the Kreb’s cycle, fatty acid synthesis, cholesterol synthesis
“-ulose” describes what kind of sugar
ketose
what is a constitutional isomer?
two structures with the same molecular formula but different connectivity
what is a stereoisomer? give the two examples.
two structures with the same molecular formula, same atomic connectivity, but different spatial arrangement.
a) enantiomers are mirror images
b) diastereomers are not mirror images
define asymmetric center, penultimate carbon, and anomeric carbon
- asymmetric center: a carbon with 4 different groups attached
- penultimate carbon: the asymmetric carbon furthest from the aldehyde or keto group
- anomeric carbon: carbon #1/asymmetric carbon in a haworth projection
describe hemiacetal, hemiketal, and acetal linkages
- a hemiacetal linkage occurs when a structure with an aldehyde forms a ring. the structure will have one OR group, and H group, and an R group
- a hemiketal linkage occurs when a structure with a ketone forms a ring. the structure will have one OR group, one OH group, and two R groups
- an acetal linkage occurs when two sugars are bound together, as opposed to binding with itself. in the case of sugars, it will be an o-glycosidic linkage
what determines a D vs L configuration in carbohydrates?
the position of the OH group on the penultimate carbon. if it is facing right it is D, left it is L.
what determines alpha vs beta configuration in carbohydrates?
if the OH group attached to the anomeric carbon is on the opposite side of the plane of the ring from C6, it is alpha. if it is on the same side, it is beta.
beta and same have four letters each!
glucopyranose exists in alpha, beta, and open-chain forms. name the relative concentrations of each at equilibrium.
alpha :about 1/3
beta: about 2/3
open chain: less than 1%
describe free aldehyde formation observed in glucose rings. why does it happen? what are the potential consequences?
in solution, glucose can reversibly form a free aldehyde at carbon 1. the opening and closing of the ring due to this reaction allows for the formation of alpha and beta anomers freely and without use of an enzyme. however, the free aldehyde group can also irreversibly form advanced glycation end products with proteins.
describe how advanced glycation end products are formed and the issues with them
they are formed when sugar levels are high. when this happens, the free aldehyde in an open chain glucose can react with other molecules irreversibly and without enzymatic regulation. this can cause the unfolding of proteins, and lead to effects typically associated with aging (crows feet, wrinkles, etc.)
structurally, what makes A and B antigens different from each other and the O antigen?
The A antigen has an additional GalNAc, and the B antigen has an additional galactose. The O antigen just contains the common core.
If a patient has blood type A, what antibodies are present? What if they have B? O?
A: B antibodies
B: A antibodies
O: A and B antibodies
Describe Hemolytic disease of the fetus and newborn (HDFN) in basic terms
this occurs when the mother and fetus have incompatible blood types. the mother must be exposed to the antigen previously for the issue occur. this will lead to the mother developing antibodies that will cross the placenta and interact with fetal RBC and cause hemolysis.